The expression in the image is $x^2 + x - 12$. To factor this quadratic expression, we need to find two numbers that multiply to $-12$ (the constant term) and add to $1$ (the coefficient of the linear term $x$).

The two numbers that satisfy these conditions are $4$ and $-3$, because:

$4 \times (-3) = -12$ $4 + (-3) = 1$

Therefore, the factorization of $x^2 + x - 12$ is:

$(x + 4)(x - 3)$

Would you like more details or have any questions about this factorization?

Here are 5 related questions for further practice:

1. How would you factor $x^2 - 5x + 6$?
2. What are the roots of the equation $x^2 + x - 12 = 0$?
3. How can you use the quadratic formula to verify the factors of $x^2 + x - 12$?
4. What is the relationship between the coefficients and the roots of a quadratic equation?
5. How can you factor a quadratic expression if the leading coefficient is not 1?

Tip: Always check your factors by multiplying them back together to ensure you get the original expression.