The expression in the image is:

$x^2 - 3x^2 - 4x + 12$

This expression seems to contain a typo or mistake, as the first two terms both have $x^2$, but with different coefficients. Let's assume the correct expression should be:

$x^2 - 3x - 4x + 12$

We can factor this expression step by step.

1. Combine Like Terms: Combine the $-3x$ and $-4x$ terms: $x^2 - 7x + 12$

2. Factor the Quadratic Expression: We need to find two numbers that multiply to 12 and add to $-7$. The numbers $-3$ and $-4$ work because: $-3 \times -4 = 12 \quad \text{and} \quad -3 + (-4) = -7$

   So, we can factor the expression as: $(x - 3)(x - 4)$

Thus, the factored form of the expression $x^2 - 7x + 12$ is $(x - 3)(x - 4)$.

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Would you like more details or have any questions? Here are some related questions:

1. How do you factor quadratics using the AC method?
2. What are the differences between factoring trinomials and binomials?
3. Can every quadratic expression be factored over the integers?
4. How can completing the square help in factoring?
5. What is the significance of the discriminant in factoring quadratic expressions?

Tip: Always double-check the coefficients and terms in an expression before attempting to factor, as errors in transcription can lead to confusion.