You provided the expression: 

\[
y^2 + 6y - 55
\]

Let's factor or solve it:

### Factoring the quadratic expression:
We need to find two numbers that multiply to give \(-55\) and add to give \(6\).

The factors of \(-55\) are: \( -11 \) and \( 5 \), since:

\[
(-11) \times 5 = -55 \quad \text{and} \quad (-11) + 5 = -6
\]

So, we can rewrite the expression as:

\[
y^2 + 6y - 55 = (y - 5)(y + 11)
\]

Thus, the factored form is:

\[
y^2 + 6y - 55 = (y - 5)(y + 11)
\]

Would you like to see the solution process in more detail or have any other questions? Here are some related questions to consider:

1. What is the method for factoring other quadratic equations?
2. How can you check if a factorization is correct?
3. What if the quadratic equation has no real factors?
4. How do you solve the equation if it's set equal to zero?
5. Can this equation be solved using the quadratic formula?

**Tip**: Always check your factorization by multiplying the factors back together to ensure they match the original expression!

Learn how to factor the quadratic equation y^2 + 6y - 55. This step-by-step guide explains factoring techniques, the use of the Factor Theorem, and how to check your solution. Ideal for students in Grades 7-9.

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