Math Problem Statement

a^3+125

Solution

The expression a3+125a^3 + 125 can be factored using the sum of cubes formula. The sum of cubes formula is:

x3+y3=(x+y)(x2xy+y2)x^3 + y^3 = (x + y)(x^2 - xy + y^2)

In your case:

  • x=ax = a
  • y=5y = 5 because 125=53125 = 5^3

Applying the formula:

a3+125=a3+53=(a+5)(a25a+25)a^3 + 125 = a^3 + 5^3 = (a + 5)(a^2 - 5a + 25)

So, the factored form of a3+125a^3 + 125 is:

(a+5)(a25a+25)(a + 5)(a^2 - 5a + 25)

Would you like more details or have any questions about this?

Here are 5 related questions:

  1. How do you factor a difference of cubes?
  2. What is the general formula for the sum of cubes?
  3. How can you verify the factorization of a cubic expression?
  4. What are some real-world applications of the sum of cubes?
  5. How would you factor a3125a^3 - 125?

Tip: Always check your factorization by expanding it back to the original expression to ensure it's correct.

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Math Problem Analysis

Mathematical Concepts

Algebra
Cubic Equations
Factoring

Formulas

Sum of Cubes Formula: x^3 + y^3 = (x + y)(x^2 - xy + y^2)

Theorems

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Suitable Grade Level

Grades 9-12