To write $9 \times 9 \times 9 \times 9 \times 9$ in exponential form with base 3, first note that $9$ can be written as $3^2$.

So:

$9 \times 9 \times 9 \times 9 \times 9 = (3^2) \times (3^2) \times (3^2) \times (3^2) \times (3^2)$

Now, using the properties of exponents, you can combine these as:

$(3^2) \times (3^2) \times (3^2) \times (3^2) \times (3^2) = 3^{2+2+2+2+2} = 3^{10}$

So, $9 \times 9 \times 9 \times 9 \times 9$ in exponential form with base 3 is $3^{10}$.

Would you like further details or have any questions?

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Here are five related questions:

1. How would you express $27 \times 27 \times 27$ in exponential form with base 3?
2. What is the value of $3^{10}$ as a numerical expression?
3. How do you express $81$ in exponential form with base 3?
4. Can you simplify the expression $9^5$ using base 3?
5. What is the general rule for converting powers of 9 into powers of 3?

Tip: When dealing with exponents, remember that multiplying the same base raised to different powers allows you to add the exponents together.