Math Problem Statement

Express S(t) in vertex form as Valerie accelerates from 35 miles per hour to enter the highway traffic. Use 3 decimal places. Hint: convert velocity from miles per hour to miles per second.

Express S(t) in vertex form as Valerie accelerates from 35 miles per hour to enter the highway traffic. Use 3 decimal places. Hint: convert velocity from miles per hour to miles per second.

Solution

We are given the formula for the position S(t)S(t) as a function of time:

S(t)=12at2+v0tS(t) = \frac{1}{2} a t^2 + v_0 t

where:

  • a=0.002miles/second2a = 0.002 \, \text{miles/second}^2 (acceleration),
  • v0v_0 is the initial velocity (Valerie's starting velocity).

Valerie's initial velocity is 35miles per hour35 \, \text{miles per hour}. First, we need to convert this to miles per second.

Step 1: Convert 35miles/hour35 \, \text{miles/hour} to miles/second\text{miles/second}

There are 3600 seconds in one hour, so we convert as follows:

v0=35miles/hour×1hour3600seconds=353600miles/second0.009722miles/secondv_0 = 35 \, \text{miles/hour} \times \frac{1 \, \text{hour}}{3600 \, \text{seconds}} = \frac{35}{3600} \, \text{miles/second} \approx 0.009722 \, \text{miles/second}

Step 2: Substitute aa and v0v_0 into the equation for S(t)S(t)

The given acceleration a=0.002miles/second2a = 0.002 \, \text{miles/second}^2, and the initial velocity v0=0.009722miles/secondv_0 = 0.009722 \, \text{miles/second}. Substituting these values into the formula:

S(t)=12×0.002×t2+0.009722×tS(t) = \frac{1}{2} \times 0.002 \times t^2 + 0.009722 \times t

Simplifying:

S(t)=0.001t2+0.009722tS(t) = 0.001 t^2 + 0.009722 t

Step 3: Express S(t)S(t) in vertex form

The vertex form of a quadratic equation is generally written as:

S(t)=a(th)2+kS(t) = a(t - h)^2 + k

where (h,k)(h, k) is the vertex of the parabola.

To convert S(t)=0.001t2+0.009722tS(t) = 0.001 t^2 + 0.009722 t to vertex form, we complete the square.

  1. Factor out 0.0010.001 from the quadratic and linear terms:

S(t)=0.001(t2+0.0097220.001t)=0.001(t2+9.722t)S(t) = 0.001 \left( t^2 + \frac{0.009722}{0.001} t \right) = 0.001 \left( t^2 + 9.722 t \right)

  1. Complete the square:
    • Take half of 9.7229.722, square it, and add it inside the parentheses.
    • Half of 9.7229.722 is 9.7222=4.861\frac{9.722}{2} = 4.861, and squaring it gives 4.8612=23.6254.861^2 = 23.625.

So we add and subtract 23.62523.625 inside the parentheses:

S(t)=0.001(t2+9.722t+23.62523.625)S(t) = 0.001 \left( t^2 + 9.722 t + 23.625 - 23.625 \right)

S(t)=0.001((t+4.861)223.625)S(t) = 0.001 \left( (t + 4.861)^2 - 23.625 \right)

  1. Distribute the 0.0010.001:

S(t)=0.001(t+4.861)20.023625S(t) = 0.001 (t + 4.861)^2 - 0.023625

Final Answer:

The position function in vertex form is:

S(t)=0.001(t+4.861)20.023625S(t) = 0.001 (t + 4.861)^2 - 0.023625

Would you like more details on any part of this calculation, or do you have any other questions?

5 Related Questions:

  1. How do you interpret the vertex of the quadratic function in terms of time and position?
  2. What does the coefficient 0.0010.001 in the vertex form represent in real-world terms?
  3. How would the equation change if Valerie started from rest instead of 35 mph?
  4. How can we calculate the time it takes for Valerie to reach a certain position using this equation?
  5. What role does completing the square play in converting to vertex form?

Tip:

Always double-check units when solving physics problems, especially when converting between different units like miles per hour and miles per second.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Kinematics

Formulas

S(t) = (1/2)at^2 + v_0t
Vertex form of a quadratic equation

Theorems

Completing the square

Suitable Grade Level

Grades 10-12