Math Problem Statement

Express the perimeter P of a rectangle as a function of the length L if the length of the rectangle is twice its width

Solution

To express the perimeter PP of a rectangle as a function of its length LL, given that the length LL is twice its width WW, follow these steps:

  1. Relate the width to the length:
    Since the length is twice the width, we can write: L=2WL = 2W Solving for WW in terms of LL: W=L2W = \frac{L}{2}

  2. Express the perimeter:
    The perimeter PP of a rectangle is given by the formula: P=2L+2WP = 2L + 2W Substitute W=L2W = \frac{L}{2} into the perimeter formula: P=2L+2(L2)P = 2L + 2\left(\frac{L}{2}\right) Simplify the expression: P=2L+L=3LP = 2L + L = 3L

So, the perimeter PP as a function of the length LL is: P(L)=3LP(L) = 3L

Would you like any details or have any questions?

Here are 5 related questions you might find interesting:

  1. What is the area of the rectangle as a function of the length LL?
  2. If the perimeter is known, how can you find the length LL of the rectangle?
  3. How does the relationship between length and width affect the area?
  4. How would the formula change if the length were three times the width?
  5. What is the diagonal of the rectangle as a function of the length LL?

Tip: Always check if dimensions are related when deriving formulas; it simplifies expressions significantly.

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Math Problem Analysis

Mathematical Concepts

Geometry
Algebra

Formulas

Perimeter of a rectangle

Theorems

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Suitable Grade Level

Grades 7-9