Math Problem Statement

Given the following equation, express p in terms of q: \[ \sqrt[3]{\frac{p}{q}} + 2 = 4 \] Also, solve the volume problem for the triangular prism as per the diagram with given dimensions.

Solution

Let's solve the problem in the image step by step.

Part (a)

The equation is:

pq3+2=4\sqrt[3]{\frac{p}{q}} + 2 = 4

To express pp in terms of qq, let's follow these steps:

  1. Isolate the cube root term: pq3=42\sqrt[3]{\frac{p}{q}} = 4 - 2 pq3=2\sqrt[3]{\frac{p}{q}} = 2

  2. Cube both sides to eliminate the cube root: pq=23\frac{p}{q} = 2^3 pq=8\frac{p}{q} = 8

  3. Solve for pp: p=8qp = 8q

Thus, pp in terms of qq is:

p=8qp = 8q


Part (b)

The formula for the volume VV of the prism is given by:

V=w×h×L2V = \frac{w \times h \times L}{2}

(i) What does this formula represent?

This formula represents the volume of a triangular prism, where:

  • ww is the width of the triangular base,
  • hh is the height of the triangular base,
  • LL is the length of the prism.

The area of the triangular base is w×h2\frac{w \times h}{2}, and the volume of the prism is the area of the base multiplied by its length LL.

(ii) Given V=300cm3V = 300 \, \text{cm}^3, w=4cmw = 4 \, \text{cm}, and L=30cmL = 30 \, \text{cm}, find hh.

We are given:

  • V=300cm3V = 300 \, \text{cm}^3,
  • w=4cmw = 4 \, \text{cm},
  • L=30cmL = 30 \, \text{cm}.

Using the volume formula:

300=4×h×302300 = \frac{4 \times h \times 30}{2}

Simplify:

300=120h2300 = \frac{120h}{2} 300=60h300 = 60h

Solve for hh:

h=30060=5cmh = \frac{300}{60} = 5 \, \text{cm}

Thus, the height hh is 5cm5 \, \text{cm}.


Summary of Answers:

  • Part (a): p=8qp = 8q
  • Part (b):
    • (i) The formula represents the volume of a triangular prism.
    • (ii) h=5cmh = 5 \, \text{cm}.

Would you like any further explanation on these steps?

Follow-up Questions:

  1. How do you find the volume of other types of prisms?
  2. What happens if pp is negative in part (a)?
  3. Can you explain why we cube both sides in part (a)?
  4. How would the formula change if the base of the prism were a rectangle?
  5. What are some other real-life examples where triangular prisms are used?

Tip:

When solving equations with cube roots or square roots, always isolate the root term first before performing the inverse operation (cubing or squaring).

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometric Volume
Prisms
Cube Roots
Linear Equations

Formulas

Cube root: \sqrt[3]{x}
Volume of a triangular prism: V = \frac{w \times h \times L}{2}

Theorems

Cube and square root properties
Prism volume theorem

Suitable Grade Level

Grades 9-11