Math Problem Statement

1000^m ÷ 100^n can be written in the form 10^z. Express z in terms of m and n.

Solution

To express 1000m÷100n1000^m \div 100^n in the form 10z10^z, let's follow these steps:

Step 1: Rewrite 1000 and 100 as powers of 10.

  • 1000=1031000 = 10^3 (since 1000=1031000 = 10^3).
  • 100=102100 = 10^2 (since 100=102100 = 10^2).

Step 2: Substitute these into the expression.

We now have: 1000m÷100n=(103)m÷(102)n.1000^m \div 100^n = (10^3)^m \div (10^2)^n.

Step 3: Apply exponent rules.

  • When raising a power to a power, multiply the exponents: (103)m=103m(10^3)^m = 10^{3m} and (102)n=102n(10^2)^n = 10^{2n}.
  • When dividing powers of the same base, subtract the exponents: 103m102n=103m2n.\frac{10^{3m}}{10^{2n}} = 10^{3m - 2n}.

Step 4: Express in the form 10z10^z.

Thus, we can express zz as: z=3m2n.z = 3m - 2n.

So, the value of zz in terms of mm and nn is z=3m2nz = 3m - 2n.

Would you like any further details on this process?

Here are five related questions:

  1. How would this change if the bases were different, such as 55 instead of 1010?
  2. What happens if you reverse the operation to 100n÷1000m100^n \div 1000^m?
  3. How can the properties of logarithms help solve such problems?
  4. What if the powers are fractional, such as 1000m/21000^{m/2}?
  5. Can you extend this to an expression involving higher powers of 10, such as 10000p10000^p?

Tip: Always remember that when dealing with powers of the same base, multiplication adds the exponents, and division subtracts them.

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Math Problem Analysis

Mathematical Concepts

Exponents
Algebra
Exponent Rules

Formulas

(a^m) ÷ (a^n) = a^(m - n)
(a^m)^n = a^(m * n)

Theorems

Laws of Exponents

Suitable Grade Level

Grades 9-11