To solve the problem and verify or generate the exponential growth table, the formula provided is:

$Q = 61,000 \times (1 + 0.045)^t$

Steps:

1. Substitute the values of $t$ from 0 to 10 into the formula.
2. Round the results to the nearest whole number.

Let's calculate the population for $t = 0$ to $t = 10$. pandas as pd

Initial population and growth rate

initial_population = 61000 growth_rate = 0.045

Calculate population for each year (t = 0 to 10)

years = list(range(11)) populations = [round(initial_population * (1 + growth_rate)**t) for t in years]

Create a table

population_table = pd.DataFrame({ "Year (t)": years, "Population": populations })

import ace_tools as tools; tools.display_dataframe_to_user(name="Exponential Growth Population Table", dataframe=population_table)I have calculated the population values for each year from $t = 0$ to $t = 10$ and displayed the table for your reference. Let me know if you want any details about the calculations or if you have further questions.

Related Questions:

1. How does the exponential growth formula change with a different growth rate?
2. What would happen to the population if the growth rate was compounded semi-annually instead of annually?
3. How can we determine the doubling time of the population using this formula?
4. What is the significance of rounding in population calculations?
5. Can this model predict long-term population trends, or are there limitations?

Tip:

Always ensure the growth rate and compounding period align when using exponential growth formulas.