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The question is asking to find the population of a city in 19 years if it has been growing at a rate of 7% per year. The current population is 800,000.

To solve this, we can use the formula for exponential growth:

\[
P(t) = P_0 \times (1 + r)^t
\]

where:
- \(P(t)\) is the future population after \(t\) years.
- \(P_0\) is the current population (800,000).
- \(r\) is the growth rate (7% or 0.07).
- \(t\) is the number of years (19).

Let's calculate the future population:

\[
P(19) = 800,000 \times (1 + 0.07)^{19}
\]

Now, I'll compute the result.The population of the city in 19 years will be approximately **2,893,222**.

Would you like further details or have any questions? Here are some related questions you might find interesting:

1. How do different growth rates affect future population estimates?
2. What is the formula for compound interest, and how is it similar to this calculation?
3. What happens to the population if the growth rate changes annually?
4. How can exponential growth apply to other real-world scenarios, such as investment or inflation?
5. What are some limitations of using exponential growth models in predicting real-world populations?

**Tip:** When dealing with exponential growth problems, always check if the rate is compounded periodically (daily, monthly, yearly) as it can significantly impact the final result.

Suppose a city with population 800,000 has been growing at a rate of 7% per year. If this rate continues, find the population of this city in 19 years.

Learn how to calculate the future population of a city given its current population of 800,000 and a 7% annual growth rate. The solution uses the exponential growth formula to determine the city's population in 19 years, which is approximately 2,893,222. Suitable for Grades 9-12.

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