A city with a population of 24,000 Is growing at a rate of 2% per year. What will the population of this city be after 8 years round your answer to the nearest whole number

To find the population of the city after 8 years, we can use the formula for exponential growth:

\[
P(t) = P_0 \times (1 + r)^t
\]

Where:
- \(P(t)\) is the population after \(t\) years,
- \(P_0\) is the initial population (24,000),
- \(r\) is the annual growth rate (2% or 0.02),
- \(t\) is the number of years (8).

Substituting the given values:

\[
P(8) = 24,000 \times (1 + 0.02)^8
\]
\[
P(8) = 24,000 \times (1.02)^8
\]
\[
P(8) \approx 24,000 \times 1.171659
\]
\[
P(8) \approx 28,119.81
\]

Rounding to the nearest whole number, the population after 8 years will be approximately **28,120**.

Would you like further details or have any questions?

Here are some related questions to explore:

1. How would the population change if the growth rate were 3% per year?
2. What would the population be after 5 years instead of 8?
3. How would the population change if it were decreasing by 1% per year?
4. What is the doubling time for a population growing at 2% annually?
5. How can this formula be applied to other real-world growth scenarios?

**Tip:** When solving exponential growth problems, ensure you use the correct rate as a decimal by dividing the percentage by 100.

A city with a population of 24,000 is growing at a rate of 2% per year. What will the population of this city be after 8 years? Round your answer to the nearest whole number.

Learn how to calculate the population of a city growing at 2% per year, starting with an initial population of 24,000. This problem uses the exponential growth formula to find the population after 8 years. Suitable for high school students in Grades 9-12.

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