Math Problem Statement

A certain substance in a laboratory is accidentally exposed to a reagent and starts to decay. However, this goes on for some time before it is noticed. Once the lab scientists notice what is happening, they decide to measure the remainder of this phenomenon until the substance has completely decayed. Hours Mass of substance (g) 4 34.5 5 21.7 6 13.7 7 8.6 8 5.4

This type of decay is known to follow an exponential curve. About how many grams of the substance were initially exposed to the reagent? ​​​​

Solution

To determine the initial mass of the substance, we can use the information provided and the fact that the decay follows an exponential curve. The general form of an exponential decay function is:

M(t)=M0ektM(t) = M_0 e^{-kt}

where:

  • M(t)M(t) is the mass at time tt,
  • M0M_0 is the initial mass (the value we want to find),
  • kk is the decay constant,
  • tt is the time in hours.

Given the data, we can use two points to determine the decay constant kk, and then find M0M_0.

Step 1: Set up two equations using the given data

We can use the data points at t=4t = 4 and t=5t = 5:

34.5=M0e4k(1)34.5 = M_0 e^{-4k} \quad \text{(1)} 21.7=M0e5k(2)21.7 = M_0 e^{-5k} \quad \text{(2)}

Step 2: Divide the two equations to eliminate M0M_0

Dividing equation (2) by equation (1):

21.734.5=M0e5kM0e4k=ek\frac{21.7}{34.5} = \frac{M_0 e^{-5k}}{M_0 e^{-4k}} = e^{-k}

ek=21.734.50.629e^{-k} = \frac{21.7}{34.5} \approx 0.629

Step 3: Solve for kk

Taking the natural logarithm on both sides:

k=ln(0.629)-k = \ln(0.629)

kln(0.629)0.464k \approx -\ln(0.629) \approx 0.464

Step 4: Substitute kk back into one of the original equations

We use equation (1):

34.5=M0e4(0.464)34.5 = M_0 e^{-4(0.464)}

34.5=M0e1.85634.5 = M_0 e^{-1.856}

M034.5e1.85634.50.156220.8gramsM_0 \approx \frac{34.5}{e^{-1.856}} \approx \frac{34.5}{0.156} \approx 220.8 \, \text{grams}

Thus, the initial mass M0M_0 of the substance exposed to the reagent was approximately 220.8 grams.

Would you like more details on any of these steps, or do you have any other questions?

Related Questions:

  1. How does the value of the decay constant kk affect the rate of decay?
  2. What happens to the mass of the substance as time goes on according to the exponential decay model?
  3. How would the result change if the mass at t=4t = 4 hours was different?
  4. Can this method be used to predict the time it takes for the substance to completely decay?
  5. How does this method compare to other types of decay models, such as linear decay?

Tip:

When dealing with exponential decay problems, using the logarithmic transformation can simplify solving for variables like the decay constant.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Exponential Decay
Algebra
Logarithms

Formulas

Exponential decay formula: M(t) = M_0 * e^(-kt)
Natural logarithm to solve for the decay constant: k = -ln(M(t2)/M(t1)) / (t2 - t1)

Theorems

Exponential Decay Theorem

Suitable Grade Level

Grades 10-12