Math Problem Statement

The function f, of, t, equals, 4300, left parenthesis, 0, point, 9, 6, right parenthesis, start superscript, 24, t, end superscriptf(t)=4300(0.96) 24t represents the change in a quantity over t days. What does the constant 0.96 reveal about the rate of change of the quantity? Answer Attempt 1 out of 2

The function is exponentially at a rate of % every .

Solution

In the given function f(t)=4300(0.96)24tf(t) = 4300(0.96)^{24t}, the constant 0.960.96 reveals important information about the rate of change of the quantity over time.

Analysis:

  • The base of the exponential, 0.960.96, represents the rate of decay in this case. Since it is less than 1, the quantity decreases over time.
  • Specifically, 0.960.96 indicates that the quantity decreases by 4% (since 10.96=0.041 - 0.96 = 0.04, or 4%) for each time period being measured.
  • Therefore, the quantity is decreasing at a rate of 4% every day.

Final Interpretation:

The constant 0.960.96 reveals that the quantity is decaying at a rate of 4% per unit of time, where the time period is determined by the factor 24t24t (for every time period of tt days).

Would you like more details or have any questions?

Here are 5 related questions to further explore:

  1. What does the initial value of 4300 in the function represent?
  2. How would the rate of decay change if the constant was 0.97 instead of 0.96?
  3. Can you determine the half-life of the quantity based on the given function?
  4. How does changing the exponent 24t24t affect the behavior of the function?
  5. What would happen to the function if the base was greater than 1?

Tip: When the base of an exponential function is less than 1, it always indicates exponential decay.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Exponential Functions
Decay Rate

Formulas

f(t) = A(b)^{kt} where A is the initial amount, b is the decay factor, k is the constant multiplier, and t is time

Theorems

Exponential Growth and Decay Theorem

Suitable Grade Level

Grades 9-12