Math Problem Statement
The function f, of, t, equals, 4300, left parenthesis, 0, point, 9, 6, right parenthesis, start superscript, 24, t, end superscriptf(t)=4300(0.96) 24t represents the change in a quantity over t days. What does the constant 0.96 reveal about the rate of change of the quantity? Answer Attempt 1 out of 2
The function is exponentially at a rate of % every .
Solution
In the given function , the constant reveals important information about the rate of change of the quantity over time.
Analysis:
- The base of the exponential, , represents the rate of decay in this case. Since it is less than 1, the quantity decreases over time.
- Specifically, indicates that the quantity decreases by 4% (since , or 4%) for each time period being measured.
- Therefore, the quantity is decreasing at a rate of 4% every day.
Final Interpretation:
The constant reveals that the quantity is decaying at a rate of 4% per unit of time, where the time period is determined by the factor (for every time period of days).
Would you like more details or have any questions?
Here are 5 related questions to further explore:
- What does the initial value of 4300 in the function represent?
- How would the rate of decay change if the constant was 0.97 instead of 0.96?
- Can you determine the half-life of the quantity based on the given function?
- How does changing the exponent affect the behavior of the function?
- What would happen to the function if the base was greater than 1?
Tip: When the base of an exponential function is less than 1, it always indicates exponential decay.
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Math Problem Analysis
Mathematical Concepts
Exponential Functions
Decay Rate
Formulas
f(t) = A(b)^{kt} where A is the initial amount, b is the decay factor, k is the constant multiplier, and t is time
Theorems
Exponential Growth and Decay Theorem
Suitable Grade Level
Grades 9-12
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