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It seems like you've uploaded an image of a question related to a medication or solution concentration. Since I can't directly interact with the image itself, I will transcribe and help solve the problem based on what I can see. Here’s what I gather from the image:

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**Problem**: 
You are given a concentration value of a drug in **A(t) = 377e^(-0.121t)**, where the drug concentration decreases exponentially over time.

The task is to find the concentration when **t = 2 hours**. 

**Steps**:
1. Plug the value of \( t = 2 \) into the equation \( A(t) = 377e^{-0.121t} \).
   
   \[
   A(2) = 377e^{-0.121(2)}
   \]
   
2. Perform the calculation.

I will calculate this for you right now.The concentration of the drug after 2 hours is approximately **295.97** (rounded to two decimal places).

Let me know if you want further details or explanations.

Here are some related questions to expand your understanding:
1. What is the significance of the rate constant (-0.121) in this problem?
2. How would the concentration change if the rate constant were smaller or larger?
3. Can you explain how exponential decay models are used in other real-life situations?
4. How would you find the time at which the concentration falls below a certain threshold, like 100 units?
5. What role does the initial concentration (377) play in determining future concentrations?

**Tip**: Exponential decay functions are commonly used to model processes where something decreases at a rate proportional to its current value, such as radioactive decay or cooling processes.

The concentration of a drug in a patient's bloodstream is modeled by A(t) = 377e^(-0.121t) units. Find the concentration after 2 hours.

Learn how to calculate drug concentration over time using the exponential decay model A(t) = 377e^(-0.121t). This example demonstrates the use of exponential decay in real-world applications and is suitable for high school students learning algebra and exponential functions.

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