Math Problem Statement

Explain chain rule with examples

Solution

The chain rule is a fundamental technique in calculus used to differentiate compositions of functions. It states that if you have a composite function f(g(x))f(g(x)), the derivative of this function with respect to xx is given by:

ddx[f(g(x))]=f(g(x))g(x)\frac{d}{dx} [f(g(x))] = f'(g(x)) \cdot g'(x)

In other words, you first differentiate the outer function ff with respect to its argument g(x)g(x), and then multiply by the derivative of the inner function gg with respect to xx.

Example 1: Differentiating sin(x2)\sin(x^2)

Let's find the derivative of h(x)=sin(x2)h(x) = \sin(x^2).

  1. Identify the outer and inner functions:

    • Outer function f(u)=sin(u)f(u) = \sin(u), where u=x2u = x^2.
    • Inner function g(x)=x2g(x) = x^2.
  2. Differentiate the outer function: f(u)=cos(u)f'(u) = \cos(u)

  3. Differentiate the inner function: g(x)=2xg'(x) = 2x

  4. Apply the chain rule: ddx[sin(x2)]=cos(x2)2x\frac{d}{dx} [\sin(x^2)] = \cos(x^2) \cdot 2x

So, the derivative of sin(x2)\sin(x^2) is 2xcos(x2)2x \cos(x^2).

Example 2: Differentiating etan(x)e^{\tan(x)}

Let's find the derivative of k(x)=etan(x)k(x) = e^{\tan(x)}.

  1. Identify the outer and inner functions:

    • Outer function f(u)=euf(u) = e^u, where u=tan(x)u = \tan(x).
    • Inner function g(x)=tan(x)g(x) = \tan(x).
  2. Differentiate the outer function: f(u)=euf'(u) = e^u

  3. Differentiate the inner function: g(x)=sec2(x)g'(x) = \sec^2(x)

  4. Apply the chain rule: ddx[etan(x)]=etan(x)sec2(x)\frac{d}{dx} [e^{\tan(x)}] = e^{\tan(x)} \cdot \sec^2(x)

So, the derivative of etan(x)e^{\tan(x)} is etan(x)sec2(x)e^{\tan(x)} \sec^2(x).

Example 3: Differentiating ln(3x2+1)\ln(3x^2 + 1)

Let's find the derivative of m(x)=ln(3x2+1)m(x) = \ln(3x^2 + 1).

  1. Identify the outer and inner functions:

    • Outer function f(u)=ln(u)f(u) = \ln(u), where u=3x2+1u = 3x^2 + 1.
    • Inner function g(x)=3x2+1g(x) = 3x^2 + 1.
  2. Differentiate the outer function: f(u)=1uf'(u) = \frac{1}{u}

  3. Differentiate the inner function: g(x)=6xg'(x) = 6x

  4. Apply the chain rule: ddx[ln(3x2+1)]=13x2+16x\frac{d}{dx} [\ln(3x^2 + 1)] = \frac{1}{3x^2 + 1} \cdot 6x

So, the derivative of ln(3x2+1)\ln(3x^2 + 1) is 6x3x2+1\frac{6x}{3x^2 + 1}.

Would you like more details or have any questions about this topic? Here are some related questions you might find interesting:

  1. What is the chain rule for higher-order derivatives?
  2. How do you differentiate cos(ln(x))\cos(\ln(x)) using the chain rule?
  3. What is the derivative of x2+1\sqrt{x^2 + 1} using the chain rule?
  4. How do you apply the chain rule to implicit differentiation?
  5. Can you explain the chain rule in the context of multivariable calculus?

Tip: When applying the chain rule, carefully identify the outer and inner functions, and take each derivative step-by-step to avoid mistakes.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Calculus
Chain Rule
Composite Functions

Formulas

Chain rule formula: d/dx[f(g(x))] = f'(g(x)) * g'(x)

Theorems

-

Suitable Grade Level

Undergraduate