Math Problem Statement

Question content area top Part 1 A man buys a racehorse for ​$20 comma 000 and enters it in two races. He plans to sell the horse​ afterward, hoping to make a profit. If the horse wins both​ races, its value will jump to ​$80 comma 000. If it wins one of the​ races, it will be worth ​$50 comma 000. If it loses both​ races, it will be worth only ​$15 comma 000. The man believes there is a 25​% chance that the horse will win the first race and a 40​% chance that it will win the second one. Assuming that the two races are independent​ events, find the​ man's expected profit. Question content area bottom Part 1 The expected profit is ​$    enter your response here. ​(Round to the nearest dollar as​ needed.)

Solution

Let's solve the problem step-by-step.

Step 1: Define the possible outcomes

We have three possible outcomes for the horse's performance in the two races:

  1. The horse wins both races: The horse's value increases to $80,000.
  2. The horse wins exactly one race: The horse's value increases to $50,000.
  3. The horse loses both races: The horse's value decreases to $15,000.

Step 2: Determine the probabilities of each outcome

We are given the following probabilities for the races:

  • The probability that the horse wins the first race is 25% (or 0.25).
  • The probability that the horse wins the second race is 40% (or 0.40).
  • The two events are independent, so we can use the multiplication rule for independent events to calculate the probabilities of each outcome:

Outcome 1: Wins both races

  • Probability = 0.25×0.40=0.100.25 \times 0.40 = 0.10

Outcome 2: Wins exactly one race

This occurs in two sub-cases:

  • Wins the first race and loses the second: 0.25×(10.40)=0.25×0.60=0.150.25 \times (1 - 0.40) = 0.25 \times 0.60 = 0.15
  • Loses the first race and wins the second: (10.25)×0.40=0.75×0.40=0.30(1 - 0.25) \times 0.40 = 0.75 \times 0.40 = 0.30

The total probability of winning exactly one race is:

  • 0.15+0.30=0.450.15 + 0.30 = 0.45

Outcome 3: Loses both races

  • Probability = (10.25)×(10.40)=0.75×0.60=0.45(1 - 0.25) \times (1 - 0.40) = 0.75 \times 0.60 = 0.45

Step 3: Determine the corresponding profits

We can now calculate the profit for each outcome:

  • Wins both races: The horse is sold for $80,000. The profit is 80,00020,000=60,00080,000 - 20,000 = 60,000.
  • Wins exactly one race: The horse is sold for $50,000. The profit is 50,00020,000=30,00050,000 - 20,000 = 30,000.
  • Loses both races: The horse is sold for $15,000. The profit is 15,00020,000=5,00015,000 - 20,000 = -5,000.

Step 4: Calculate the expected profit

The expected profit is the sum of the products of each possible profit and its corresponding probability:

Expected Profit=(60,000×0.10)+(30,000×0.45)+(5,000×0.45)\text{Expected Profit} = (60,000 \times 0.10) + (30,000 \times 0.45) + (-5,000 \times 0.45)

Expected Profit=6,000+13,5002,250=17,250\text{Expected Profit} = 6,000 + 13,500 - 2,250 = 17,250

Final Answer:

The expected profit is $17,250.


Would you like more details or have any questions about the solution? Here are some related questions for further exploration:

  1. How would the expected profit change if the probability of winning the first race were increased to 50%?
  2. What would happen to the expected profit if the value of the horse after losing both races increased to $25,000?
  3. If the cost of the horse was $25,000 instead of $20,000, how would this affect the expected profit?
  4. How can we calculate the expected value of an event with three possible outcomes?
  5. What is the difference between independent and dependent events in probability theory?

Tip: Remember that when calculating the expected value, it's important to account for all possible outcomes and their probabilities, and multiply each profit by its associated probability.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Probability
Expected Value
Independent Events

Formulas

Expected Profit = (Profit1 * Probability1) + (Profit2 * Probability2) + (Profit3 * Probability3)

Theorems

Multiplication Rule for Independent Events

Suitable Grade Level

Grades 9-11