Math Problem Statement

  1. Write logb (xy) in expanded form. (i) logb (x) logb (y) (ii) logb (x) − logb (y) (iii) logb (x) logb (y) (iv) logb (x) + logb (y)
  2. Write logb ( x y ) in expanded form. (i) logb (x) logb (y) (ii) logb (x) − logb (y) (iii) logb (x) logb (y) (iv) logb (x) + logb (y)
  3. The expression logb (x p ) equals (i) p logb (x) (ii) [logb (x)]p (iii) logb (x) + logb (p) (iv) logb (x) p
  4. The statment logb (x + y) = logb (x) + logb (y) is (i) True (ii) False
  5. Which of the following equals log2 (x)? (i) log5 (x) log2 (5) (ii) log5 (x) 2 (iii) log5 (x) + log5 (2) (iv) log5 (x) log5 (2)

Solution

Let's break down each of the logarithmic expressions and analyze the correct choices for each problem.

1. Write logb(xy)\log_b (xy) in expanded form:

The property of logarithms that applies here is: logb(xy)=logb(x)+logb(y)\log_b (xy) = \log_b (x) + \log_b (y) This is the product rule for logarithms. Therefore, the correct expanded form is:

  • (iv) logb(x)+logb(y)\log_b (x) + \log_b (y)

2. Write logb(xy)\log_b \left(\frac{x}{y}\right) in expanded form:

The property of logarithms that applies here is: logb(xy)=logb(x)logb(y)\log_b \left( \frac{x}{y} \right) = \log_b (x) - \log_b (y) This is the quotient rule for logarithms. Therefore, the correct expanded form is:

  • (ii) logb(x)logb(y)\log_b (x) - \log_b (y)

3. The expression logb(xp)\log_b (x^p) equals:

The property of logarithms that applies here is: logb(xp)=plogb(x)\log_b (x^p) = p \cdot \log_b (x) This is the power rule for logarithms. Therefore, the correct expanded form is:

  • (i) plogb(x)p \cdot \log_b (x)

4. The statement logb(x+y)=logb(x)+logb(y)\log_b (x + y) = \log_b (x) + \log_b (y) is:

This statement is False. The property that logb(x+y)=logb(x)+logb(y)\log_b (x + y) = \log_b (x) + \log_b (y) does not hold in general logarithmic identities. Instead, logb\log_b only works with products, quotients, and powers as shown above. So the correct answer is:

  • (ii) False

5. Which of the following equals log2(x)\log_2 (x)?

To convert between different logarithmic bases, you can use the change of base formula: logb(x)=logk(x)logk(b)\log_b (x) = \frac{\log_k (x)}{\log_k (b)} Using this formula, log2(x)\log_2 (x) can be written in terms of base 5 as: log2(x)=log5(x)log5(2)\log_2 (x) = \frac{\log_5 (x)}{\log_5 (2)} Thus, the correct answer is:

  • (iv) log5(x)log5(2)\frac{\log_5 (x)}{\log_5 (2)}

Summary of correct answers:

  1. (iv) logb(x)+logb(y)\log_b (x) + \log_b (y)
  2. (ii) logb(x)logb(y)\log_b (x) - \log_b (y)
  3. (i) plogb(x)p \log_b (x)
  4. (ii) False
  5. (iv) log5(x)log5(2)\frac{\log_5 (x)}{\log_5 (2)}

Would you like further explanations or have any additional questions?

5 Related Questions:

  1. How does the logarithmic change of base formula work?
  2. Can you provide examples of logarithm properties with real numbers?
  3. What are the key differences between natural logarithms and base-10 logarithms?
  4. How can logarithms be used to solve exponential equations?
  5. How do you simplify expressions with multiple logarithmic rules?

Tip:

Remember that logarithmic properties are powerful tools for simplifying expressions, but always ensure you're applying the correct rule for products, quotients, or powers!

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Math Problem Analysis

Mathematical Concepts

Logarithms
Algebra

Formulas

logb(xy) = logb(x) + logb(y)
logb(x/y) = logb(x) - logb(y)
logb(x^p) = p * logb(x)
Change of base formula: logb(x) = logk(x) / logk(b)

Theorems

Product Rule of Logarithms
Quotient Rule of Logarithms
Power Rule of Logarithms

Suitable Grade Level

Grades 9-12