The expression provided is $(2x + 2)(3x - 8)$. Let's expand and simplify it step by step.

Steps:

1. Use the distributive property (FOIL method): $(2x + 2)(3x - 8) = (2x \cdot 3x) + (2x \cdot -8) + (2 \cdot 3x) + (2 \cdot -8)$

2. Multiply each term: $2x \cdot 3x = 6x^2, \quad 2x \cdot -8 = -16x, \quad 2 \cdot 3x = 6x, \quad 2 \cdot -8 = -16$

3. Combine the results: $6x^2 - 16x + 6x - 16$

4. Combine like terms ($-16x + 6x$): $6x^2 - 10x - 16$

Final Answer:

$6x^2 - 10x - 16$

Would you like a detailed explanation of any step or more examples of similar problems?

Related Questions:

1. What is the FOIL method, and how does it apply to expanding binomials?
2. How do you factorize a quadratic expression like $6x^2 - 10x - 16$?
3. Can the quadratic $6x^2 - 10x - 16$ be solved for its roots using the quadratic formula?
4. How do you apply the distributive property to expressions with more than two terms in each factor?
5. How does expanding polynomials relate to solving real-world problems?

Tip:

When expanding binomials, always organize terms neatly to avoid missing any pair of products.