To expand the expression $(2x + 2)(x - 9)$, we will apply the distributive property (also known as the FOIL method for binomials).

1. First, multiply the first terms:
   $2x \times x = 2x^2$

2. Next, multiply the outer terms:
   $2x \times -9 = -18x$

3. Then, multiply the inner terms:
   $2 \times x = 2x$

4. Finally, multiply the last terms:
   $2 \times -9 = -18$

Now, combine all these terms together:
$2x^2 - 18x + 2x - 18$

Combine like terms:
$2x^2 - 16x - 18$

So, the expanded form of $(2x + 2)(x - 9)$ is: $2x^2 - 16x - 18$

Would you like more details or further explanation?

Here are 5 related questions you might want to consider:

1. How do you factor quadratic expressions like $2x^2 - 16x - 18$?
2. What are the solutions to $2x^2 - 16x - 18 = 0$?
3. Can you simplify $(2x + 2)(x - 9)$ further if given specific values of $x$?
4. How does the distributive property work with trinomials?
5. What happens when you apply the FOIL method to different types of binomials?

Tip: Always combine like terms after distributing to simplify your expression fully!