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We are given the recurrence relation \( u_{n+1} = \frac{1}{5} u_n \) and the initial value \( u_1 = 5 \). The problem asks to find the exact value of:

\[
\sum_{r=1}^{\infty} u_r - \sum_{r=1}^{4} u_r
\]

### Step 1: Understanding the Sequence
The recurrence relation tells us that each term in the sequence is a fifth of the previous term. So, we can compute the first few terms of the sequence:

- \( u_1 = 5 \)
- \( u_2 = \frac{1}{5} \times u_1 = \frac{1}{5} \times 5 = 1 \)
- \( u_3 = \frac{1}{5} \times u_2 = \frac{1}{5} \times 1 = \frac{1}{5} \)
- \( u_4 = \frac{1}{5} \times u_3 = \frac{1}{5} \times \frac{1}{5} = \frac{1}{25} \)
- \( u_5 = \frac{1}{5} \times u_4 = \frac{1}{5} \times \frac{1}{25} = \frac{1}{125} \)

### Step 2: General Term
From this, we can see that the general term of the sequence is given by:

\[
u_n = 5 \times \left( \frac{1}{5} \right)^{n-1} = 5 \times 5^{-(n-1)} = 5 \times \frac{1}{5^{n-1}} = \frac{5}{5^{n-1}} = \frac{1}{5^{n-1}}.
\]

### Step 3: Sum of Infinite Series
Now, let's calculate the sum of the infinite series \( \sum_{r=1}^{\infty} u_r \). This is a geometric series with the first term \( u_1 = 5 \) and common ratio \( \frac{1}{5} \). The sum of an infinite geometric series is given by:

\[
S = \frac{a}{1 - r}
\]
where \( a \) is the first term and \( r \) is the common ratio.

For this series:
- \( a = 5 \)
- \( r = \frac{1}{5} \)

Thus, the sum of the infinite series is:

\[
S_{\infty} = \frac{5}{1 - \frac{1}{5}} = \frac{5}{\frac{4}{5}} = \frac{5 \times 5}{4} = \frac{25}{4}.
\]

### Step 4: Sum of First Four Terms
Next, let's compute the sum of the first four terms:

\[
S_4 = u_1 + u_2 + u_3 + u_4 = 5 + 1 + \frac{1}{5} + \frac{1}{25}.
\]

To simplify:

\[
S_4 = 5 + 1 + 0.2 + 0.04 = 6.24.
\]

### Step 5: Final Expression
We need to compute:

\[
\sum_{r=1}^{\infty} u_r - \sum_{r=1}^{4} u_r = S_{\infty} - S_4.
\]

Substituting the values:

\[
= \frac{25}{4} - 6.24.
\]

First, let's express \( 6.24 \) as a fraction:

\[
6.24 = \frac{624}{100} = \frac{156}{25}.
\]

Now, subtracting the two values:

\[
\frac{25}{4} - \frac{156}{25}.
\]

We will find a common denominator and subtract the fractions. Let me calculate this step:

\[
\text{LCM of 4 and 25 is 100, so: }
\]

\[
\frac{25}{4} = \frac{625}{100}, \quad \frac{156}{25} = \frac{624}{100}.
\]

Thus:

\[
\frac{625}{100} - \frac{624}{100} = \frac{1}{100}.
\]

### Final Answer:
The exact value of the expression is:

\[
\boxed{\frac{1}{100}}.
\]

Would you like more details or have any further questions?

---

**Relative questions:**
1. How do you generalize the sum of geometric series for different common ratios?
2. What is the effect of different starting values on the infinite sum of the series?
3. Can the sum of a geometric series ever diverge, and under what conditions?
4. How do you convert between decimal and fractional representations accurately?
5. What are the properties of the recurrence relation in the context of this problem?

**Tip:** Always remember to check the convergence of a series before computing its infinite sum.

If u_{n+1} = 1/5 u_n, where u_1 = 5, find the exact value of ∑_{r=1}^{∞} u_r - ∑_{r=1}^{4} u_r.

Learn how to find the exact value of a recurrence relation sequence with the formula u_{n+1} = 1/5 u_n and u_1 = 5. The problem includes finding the sum of an infinite geometric series and subtracting the sum of the first four terms.

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