Let's analyze the graphs and the questions.

You are given two graphs, $y = f(x)$ on the left and $y = g(x)$ on the right, and the following tasks:

(a) $(f - g)(2)$:

This means you need to calculate $f(2) - g(2)$.

• Look at $x = 2$ on both graphs.
  • For $f(x)$ (left graph), at $x = 2$, the function value is $f(2) = 2$.
  • For $g(x)$ (right graph), at $x = 2$, the function value is $g(2) = 3$.

Thus, $(f - g)(2) = f(2) - g(2) = 2 - 3 = -1$.

(b) $(fg)(3)$:

This means you need to calculate $f(3) \times g(3)$.

• Look at $x = 3$ on both graphs.
  • For $f(x)$ (left graph), at $x = 3$, the function value is $f(3) = 3$.
  • For $g(x)$ (right graph), at $x = 3$, the function value is $g(3) = 2$.

Thus, $(fg)(3) = f(3) \times g(3) = 3 \times 2 = 6$.

Final Answers:

• (a) $(f - g)(2) = -1$
• (b) $(fg)(3) = 6$

Would you like further explanations or details on any part?

Related Questions:

1. What is $f(1) - g(1)$?
2. How would you compute $(fg)(1)$?
3. Can you find $f(0) - g(0)$?
4. What is $(f - g)(4)$?
5. How do you calculate $(fg)(0)$?

Tip:

Always make sure to read the values from the graph carefully, focusing on the corresponding $y$-values for the given $x$-coordinates.