To evaluate \(9!\) (9 factorial), you multiply all positive integers from 1 to 9:

\[
9! = 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1
\]

Calculating this step by step:

- \(9 \times 8 = 72\)
- \(72 \times 7 = 504\)
- \(504 \times 6 = 3024\)
- \(3024 \times 5 = 15120\)
- \(15120 \times 4 = 60480\)
- \(60480 \times 3 = 181440\)
- \(181440 \times 2 = 362880\)
- \(362880 \times 1 = 362880\)

Thus, 

\[
9! = 362880
\]

Would you like more details or do you have any questions? Here are some related questions you might find interesting:

1. What is the value of \(10!\)?
2. How is factorial notation used in combinations and permutations?
3. Can you explain how to compute \(n!\) for larger values of \(n\)?
4. What are some applications of factorials in mathematics?
5. How does the concept of factorial extend to non-integer values (gamma function)? 

**Tip:** Factorials grow very quickly; \(n!\) can become very large even for small \(n\).

Discover the step-by-step evaluation of 9! (9 factorial) and understand the concept of factorials in mathematics. This solution details the multiplication of integers from 1 to 9 and highlights the rapid growth of factorial values. Suitable for students in Grades 5-7.

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