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The problem involves evaluating the product:

\[
\left(1 + \frac{1}{9}\right) \times \left(1 + \frac{1}{8}\right) \times \left(1 + \frac{1}{7}\right) \times \dots \times \left(1 + \frac{1}{2}\right)
\]

Let's simplify each term in the product individually:

1. Each term can be rewritten as:
   \[
   1 + \frac{1}{n} = \frac{n + 1}{n}
   \]

2. Therefore, the product becomes:
   \[
   \frac{10}{9} \times \frac{9}{8} \times \frac{8}{7} \times \dots \times \frac{3}{2}
   \]

3. Notice that this sequence has a telescoping effect, where most terms in the numerator and denominator will cancel each other out. Specifically:

   \[
   \frac{10}{9} \times \frac{9}{8} \times \frac{8}{7} \times \dots \times \frac{3}{2} = \frac{10}{2} = 5
   \]

4. Therefore, the result of the entire product is:

\[
\boxed{5}
\]

The correct answer is (B) 5.

---

Would you like a further breakdown of telescoping products or have any questions on similar problems? Here are some additional questions that might expand your understanding:

1. How does the telescoping property simplify complex products or sums?
2. What other types of mathematical expressions benefit from telescoping?
3. Could a similar technique apply to sums rather than products?
4. How would this approach change if terms didn’t fully cancel?
5. What other problems could be simplified using partial fraction decomposition?

**Tip:** When faced with a long sequence of fractions in a product, look for a telescoping pattern—it often simplifies calculations significantly!

This product is equal to: (1 + 1/9) × (1 + 1/8) × (1 + 1/7) × ... × (1 + 1/2)

Learn how to evaluate a telescoping product sequence with fractions in the form (1 + 1/n) × (1 + 1/(n-1)) × ... × (1 + 1/2). This problem uses the concept of telescoping products to simplify a complex multiplication series and is suitable for students in Grades 8-10.

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