Math Problem Statement

evaluate function x=1.5 f(x)=x²-2x+2

Solution

To evaluate the function f(x)=x22x+2f(x) = x^2 - 2x + 2 at x=1.5x = 1.5, we substitute x=1.5x = 1.5 into the function:

f(1.5)=(1.5)22(1.5)+2f(1.5) = (1.5)^2 - 2(1.5) + 2

Now, let's compute each term:

  1. Calculate (1.5)2(1.5)^2: (1.5)2=2.25(1.5)^2 = 2.25

  2. Calculate 2×1.52 \times 1.5: 2×1.5=32 \times 1.5 = 3

  3. Substitute these values back into the function: f(1.5)=2.253+2f(1.5) = 2.25 - 3 + 2

  4. Simplify the expression: f(1.5)=2.253+2=1.25f(1.5) = 2.25 - 3 + 2 = 1.25

So, the value of the function f(x)f(x) at x=1.5x = 1.5 is:

1.25\boxed{1.25}

Would you like more details or have any questions?

Here are some related questions for further exploration:

  1. What is the vertex form of the quadratic function f(x)=x22x+2f(x) = x^2 - 2x + 2?
  2. How do you find the roots of the quadratic function f(x)=x22x+2f(x) = x^2 - 2x + 2?
  3. What is the axis of symmetry for the function f(x)=x22x+2f(x) = x^2 - 2x + 2?
  4. How do you determine if a quadratic function opens upwards or downwards?
  5. What is the minimum or maximum value of f(x)=x22x+2f(x) = x^2 - 2x + 2 and at what point does it occur?

Tip: When evaluating functions, carefully substitute values and simplify step-by-step to avoid mistakes.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Function Evaluation

Formulas

f(x) = x^2 - 2x + 2

Theorems

Substitution in Function Evaluation

Suitable Grade Level

Grades 8-10