Math Problem Statement

lim n-> infinit n^2* integrala de la n la n+1 din ln(1+x/(1+x^3)) dx

Solution

To evaluate the expression

limnn2nn+1ln(1+x1+x3)dx\lim_{n \to \infty} n^2 \cdot \int_{n}^{n+1} \ln\left(1 + \frac{x}{1 + x^3}\right) \, dx

let's proceed with analyzing the behavior of the integrand and applying some asymptotic analysis as nn \to \infty.

Step 1: Analyzing the Integrand

We have: ln(1+x1+x3).\ln\left(1 + \frac{x}{1 + x^3}\right). As xx \to \infty, the term x1+x3\frac{x}{1 + x^3} tends to zero since the denominator 1+x31 + x^3 grows much faster than the numerator xx. Hence, we can use the approximation ln(1+u)u\ln(1 + u) \approx u for uu close to zero.

Thus, for large nn, we can approximate: ln(1+x1+x3)x1+x3.\ln\left(1 + \frac{x}{1 + x^3}\right) \approx \frac{x}{1 + x^3}.

Step 2: Approximating the Integral

Now, we want to evaluate: nn+1x1+x3dx.\int_{n}^{n+1} \frac{x}{1 + x^3} \, dx. For large xx, we approximate 1+x3x31 + x^3 \approx x^3, so x1+x3xx3=1x2.\frac{x}{1 + x^3} \approx \frac{x}{x^3} = \frac{1}{x^2}. Thus, the integral becomes approximately: nn+11x2dx.\int_{n}^{n+1} \frac{1}{x^2} \, dx.

Step 3: Evaluating the Approximate Integral

Now we compute: nn+11x2dx=[1x]nn+1=1n+1+1n.\int_{n}^{n+1} \frac{1}{x^2} \, dx = \left[-\frac{1}{x}\right]_{n}^{n+1} = -\frac{1}{n+1} + \frac{1}{n}. Simplifying, we get: nn+11x2dx1n1n+1.\int_{n}^{n+1} \frac{1}{x^2} \, dx \approx \frac{1}{n} - \frac{1}{n+1}.

Using the approximation 1n1n+11n2\frac{1}{n} - \frac{1}{n+1} \approx \frac{1}{n^2} for large nn, the integral is approximately 1n2\frac{1}{n^2}.

Step 4: Taking the Limit

Now we have: limnn2nn+1ln(1+x1+x3)dxlimnn21n2=limn1=1.\lim_{n \to \infty} n^2 \cdot \int_{n}^{n+1} \ln\left(1 + \frac{x}{1 + x^3}\right) \, dx \approx \lim_{n \to \infty} n^2 \cdot \frac{1}{n^2} = \lim_{n \to \infty} 1 = 1.

Final Answer

limnn2nn+1ln(1+x1+x3)dx=1.\lim_{n \to \infty} n^2 \cdot \int_{n}^{n+1} \ln\left(1 + \frac{x}{1 + x^3}\right) \, dx = 1.

Would you like more details on the steps or have any further questions?


Here are some related questions that expand on this topic:

  1. How can we generalize this approach for other integrals with similar limits?
  2. What other approximation techniques could be applied for different asymptotic behavior?
  3. How does the choice of approximation influence the result in limit calculations?
  4. Could we approach this problem using numerical methods? If so, how?
  5. What is the role of the Taylor series in such asymptotic limit problems?

Tip: When evaluating limits of integrals as nn \to \infty, approximating the integrand based on its behavior for large nn can often simplify the calculation considerably.

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Math Problem Analysis

Mathematical Concepts

Calculus
Limits
Asymptotic Analysis
Integral Approximation

Formulas

Limit of an integral as n approaches infinity
Approximation of ln(1 + u) ≈ u for u close to zero
Integral approximation using 1/x^2

Theorems

Asymptotic Approximation
Limit of Integrals
Logarithmic Approximations

Suitable Grade Level

Undergraduate Mathematics