Math Problem Statement
- Evaluate the following iterated integrals (a) Z 3 0 Z π/2 0 x2 sin(y) dydx (b) Z 5 3 Z 5 0 dydx x + y (c) Z Z D 23x y dA, where D = [−2, 4] × [1, 3].
Solution
Let’s go through each of the iterated integrals step by step.
(a) Evaluate the double integral
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Integrate with respect to first:
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Now, integrate with respect to :
So, the value of the integral is:
(b) Evaluate the double integral
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Integrate with respect to first. We treat as a constant: This simplifies to:
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Now, integrate with respect to : This integral requires substitution and can be simplified using integration techniques. For brevity here, we will compute this integral as: So, the value of the integral is approximately:
(c) Evaluate the double integral over region
Here, . The integral becomes:
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Integrate with respect to :
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Now, integrate with respect to : Evaluating this gives: So, the final result is: Thus, the value of the integral is:
Summary of Results:
- (a)
- (b)
- (c)
Would you like more details on any step or method used?
Here are five related questions:
- What are the basic properties of double integrals?
- How does changing the order of integration affect the result?
- Can you apply Fubini’s theorem to non-rectangular regions?
- What is the meaning of an iterated integral in terms of volume?
- How can substitution help simplify iterated integrals?
Tip: Always check if symmetry can simplify the limits of integration before starting.
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Math Problem Analysis
Mathematical Concepts
Calculus
Double Integrals
Iterated Integrals
Integration Techniques
Formulas
Double integral formula ∫∫_D f(x, y) dA
Integration of trigonometric functions ∫ sin(y) dy = -cos(y)
Logarithmic integration ∫ 1/(x + y) dy = ln(x + y)
Theorems
Fubini's Theorem for double integrals
Suitable Grade Level
Undergraduate Calculus
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