Math Problem Statement

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Show that \( \int_0^\infty e^{-x^2} x^9 \, dx = 12 \).

Solution

To solve the integral

0ex2x9dx=12,\int_0^\infty e^{-x^2} x^9 \, dx = 12,

we will proceed step by step, leveraging the Gamma function properties and substitutions.


Step 1: General Gamma Function Relation

The Gamma function is defined as:

Γ(z)=0tz1etdt,\Gamma(z) = \int_0^\infty t^{z-1} e^{-t} \, dt,

and a key property of definite integrals involving ex2e^{-x^2} is:

0x2nex2dx=Γ(n+12)2.\int_0^\infty x^{2n} e^{-x^2} \, dx = \frac{\Gamma\left(n + \frac{1}{2}\right)}{2}.

Here, x2nx^{2n} indicates even powers of xx. For odd powers x2n+1x^{2n+1}, the integral equals 0 because the function would be odd over symmetric limits.


Step 2: Relate the Given Integral to the Gamma Function

In the given problem, we have x9ex2x^9 e^{-x^2}, where x9=x24+1xx^9 = x^{2 \cdot 4 + 1} x. Thus, we decompose this as follows:

Let x=t1/2x = t^{1/2}, or t=x2t = x^2. This implies dx=12t1/2dtdx = \frac{1}{2} t^{-1/2} dt.

Substituting tt into the integral:

0x9ex2dx=0(t1/2)9et12t1/2dt.\int_0^\infty x^9 e^{-x^2} \, dx = \int_0^\infty \left(t^{1/2}\right)^9 e^{-t} \cdot \frac{1}{2} t^{-1/2} \, dt.

Simplify:

0x9ex2dx=120t9/2t1/2etdt.\int_0^\infty x^9 e^{-x^2} \, dx = \frac{1}{2} \int_0^\infty t^{9/2} t^{-1/2} e^{-t} \, dt.

=120t(9/2)+(1/2)etdt.= \frac{1}{2} \int_0^\infty t^{(9/2) + (-1/2)} e^{-t} \, dt.

=120t4etdt.= \frac{1}{2} \int_0^\infty t^{4} e^{-t} \, dt.


Step 3: Use the Gamma Function

The remaining integral is now in the form of the Gamma function:

0t4etdt=Γ(4+1)=Γ(5).\int_0^\infty t^{4} e^{-t} \, dt = \Gamma(4 + 1) = \Gamma(5).

The Gamma function satisfies the property:

Γ(n)=(n1)!.\Gamma(n) = (n-1)!.

Thus:

Γ(5)=4!=24.\Gamma(5) = 4! = 24.

Therefore:

0x9ex2dx=1224=12.\int_0^\infty x^9 e^{-x^2} \, dx = \frac{1}{2} \cdot 24 = 12.


Final Answer:

0ex2x9dx=12.\int_0^\infty e^{-x^2} x^9 \, dx = 12.

This confirms the result.


Would you like additional details on the Gamma function or related integrals?


5 Related Questions:

  1. What is the Gamma function and how is it related to factorials?
  2. How can you compute integrals of the form 0xnex2dx\int_0^\infty x^{n} e^{-x^2} dx for other values of nn?
  3. What substitution rules are commonly used to solve these types of integrals?
  4. Can we solve this problem using numerical integration instead of analytical methods?
  5. How does the property of symmetry affect integrals involving even and odd powers of xx?

Tip:

Always check if a given integral can be expressed in terms of standard functions like Gamma or Beta functions to simplify the evaluation process.

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Math Problem Analysis

Mathematical Concepts

Gamma Function
Integral Calculus
Substitution

Formulas

Gamma function: \( \Gamma(z) = \int_0^\infty t^{z-1} e^{-t} \, dt \)
Integral property: \( \int_0^\infty x^{2n} e^{-x^2} \, dx = \frac{\Gamma(n + \frac{1}{2})}{2} \)
Gamma function property: \( \Gamma(n) = (n-1)! \)

Theorems

Gamma Function Theorem
Integral Transformation Theorem

Suitable Grade Level

Undergraduate (Calculus and Advanced Mathematics)