Math Problem Statement

f(x)= 3/2 x (4/3)^1 - 1 x=1 f(x)=? y-intercept=? horizontal asymptote of the exponential function=? graph this

Solution

Here's the graph of the function f(x)=32x(43)x1f(x) = \frac{3}{2} x \left( \frac{4}{3} \right)^x - 1.

Summary:

  1. f(1)=1f(1) = 1
  2. yy-intercept: 1-1
  3. Horizontal asymptote: y=1y = -1

Would you like further details on any of these steps?

Here are some related questions to consider:

  1. What would happen to the function if we changed the base of the exponent?
  2. How does the coefficient 32\frac{3}{2} affect the shape of the graph?
  3. What if we changed the constant 1-1 to a different number?
  4. How does this function differ from a basic exponential function?
  5. What would the graph look like over a larger interval of xx-values?

Tip: Horizontal asymptotes in exponential functions can reveal the long-term behavior of the function as xx \to \infty or xx \to -\infty.

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Math Problem Analysis

Mathematical Concepts

Exponential Functions
Function Evaluation
Intercepts
Asymptotes
Graphing

Formulas

f(x) = (3/2) * x * (4/3)^x - 1
Evaluation of exponential function at x = 1
y-intercept of f(x): set x = 0
Horizontal asymptote: y = -1 for f(x) as x approaches infinity

Theorems

Properties of Exponential Functions
Behavior of Asymptotes in Exponential Functions

Suitable Grade Level

Grades 10-12