Math Problem Statement

g(z)=z^2+8z+10 g(p+5)=

Solution

To evaluate g(p+5)g(p+5) for g(z)=z2+8z+10g(z) = z^2 + 8z + 10, we need to substitute z=p+5z = p + 5 into the expression.

  1. Substitute z=p+5z = p + 5 into g(z)g(z):

    g(p+5)=(p+5)2+8(p+5)+10g(p+5) = (p+5)^2 + 8(p+5) + 10

  2. Expand (p+5)2(p+5)^2:

    (p+5)2=p2+10p+25(p+5)^2 = p^2 + 10p + 25

  3. Expand 8(p+5)8(p+5):

    8(p+5)=8p+408(p+5) = 8p + 40

  4. Substitute these expansions back into the expression:

    g(p+5)=p2+10p+25+8p+40+10g(p+5) = p^2 + 10p + 25 + 8p + 40 + 10

  5. Combine like terms:

    g(p+5)=p2+18p+75g(p+5) = p^2 + 18p + 75

Thus, the result is:

g(p+5)=p2+18p+75g(p+5) = p^2 + 18p + 75

Would you like further explanation on any step?

Here are related questions for practice:

  1. What is g(p3)g(p-3) for the same function g(z)=z2+8z+10g(z) = z^2 + 8z + 10?
  2. How would you find g(2p)g(2p)?
  3. What is the derivative of g(z)=z2+8z+10g(z) = z^2 + 8z + 10?
  4. How would g(z)g(z) change if the constant term were different?
  5. What is the value of g(p+5)g(p+5) if p=3p = 3?

Tip: When substituting variables, expand terms carefully to avoid calculation errors with each distribution step.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Substitution

Formulas

Quadratic function g(z) = z^2 + 8z + 10
Substitution of variables
Expanding binomials

Theorems

Distributive Property

Suitable Grade Level

Grades 8-10