Math Problem Statement

Evaluate f ( x − 4 ) f ( x

4 ) for the function f ( x )

x 2 − 3 x f ( x )

x 2

3 x

Solution

Given the function f(x)=x23xf(x) = x^2 - 3x, we are asked to evaluate f(x4)f(x - 4).

Step 1: Substitute x4x - 4 into the function

To find f(x4)f(x - 4), substitute x4x - 4 for xx in the expression for f(x)f(x):

f(x4)=(x4)23(x4)f(x - 4) = (x - 4)^2 - 3(x - 4)

Step 2: Expand (x4)2(x - 4)^2 and simplify

First, expand the square: (x4)2=x28x+16(x - 4)^2 = x^2 - 8x + 16

Now, distribute the -3 over (x4)(x - 4): 3(x4)=3x+12-3(x - 4) = -3x + 12

Step 3: Combine all terms

Now combine the two expressions: f(x4)=(x28x+16)+(3x+12)f(x - 4) = (x^2 - 8x + 16) + (-3x + 12) Simplify by combining like terms: f(x4)=x211x+28f(x - 4) = x^2 - 11x + 28

Final Answer:

f(x4)=x211x+28f(x - 4) = x^2 - 11x + 28

Do you need further details or explanations?

Here are 5 related questions for practice:

  1. What is f(x+3)f(x + 3) for the function f(x)=x23xf(x) = x^2 - 3x?
  2. How would you solve f(2)f(2) for the same function?
  3. How do you find the vertex of the quadratic function f(x)=x211x+28f(x) = x^2 - 11x + 28?
  4. What are the roots of f(x4)=0f(x - 4) = 0?
  5. How would you differentiate f(x)=x23xf(x) = x^2 - 3x?

Tip: When substituting into functions, simplify expressions step by step to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Algebra
Function Substitution
Quadratic Functions
Simplification

Formulas

f(x) = x^2 - 3x
f(x - 4) = (x - 4)^2 - 3(x - 4)

Theorems

Expansion of binomials
Combining like terms

Suitable Grade Level

Grades 8-10