Let's solve the problem step by step.

Given Functions:

1. $f(x) = -4x - 1$
2. $g(x) = 2x^3 + 2$

Find $f(6)$ and $g(-3)$.

Step 1: Calculate $f(6)$

We substitute $x = 6$ into $f(x)$: $f(x) = -4x - 1$ $f(6) = -4(6) - 1 = -24 - 1 = -25$

So, $f(6) = -25$.

Step 2: Calculate $g(-3)$

We substitute $x = -3$ into $g(x)$: $g(x) = 2x^3 + 2$ $g(-3) = 2(-3)^3 + 2$ First, calculate $(-3)^3$: $(-3)^3 = -27$ Then substitute: $g(-3) = 2(-27) + 2 = -54 + 2 = -52$

So, $g(-3) = -52$.

Final Answers:

• $f(6) = -25$
• $g(-3) = -52$

Would you like further clarification, or do you have additional questions?

Related Questions:

1. What is the derivative of $f(x)$ and $g(x)$?
2. How would you solve for $x$ if $f(x) = 0$?
3. What is $g(2)$ and $f(-5)$?
4. If $h(x) = f(x) + g(x)$, what is $h(6)$?
5. How do you find the inverse of $f(x)$, if it exists?

Tip:

Always substitute values carefully and simplify step by step to avoid mistakes!