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The problem asks for the value of \(\left(\frac{7}{8}\right)^{-2}\).

To solve this:

1. **Reciprocal Rule for Negative Exponents**: When a fraction is raised to a negative exponent, you take the reciprocal of the fraction and then raise it to the positive of that exponent.

   \[
   \left(\frac{7}{8}\right)^{-2} = \left(\frac{8}{7}\right)^{2}
   \]

2. **Square the Fraction**: Now, raise the fraction \(\frac{8}{7}\) to the power of 2.

   \[
   \left(\frac{8}{7}\right)^{2} = \frac{8^2}{7^2} = \frac{64}{49}
   \]

So, the value of \(\left(\frac{7}{8}\right)^{-2}\) is \(\frac{64}{49}\).

Would you like more details on any part of this explanation, or do you have any other questions?

Here are 5 related questions:
1. How do you simplify expressions with negative exponents?
2. What is the process for converting improper fractions to mixed numbers?
3. How do you handle exponents in fractions with both positive and negative bases?
4. What are the general rules for exponents, and how do they apply to fractions?
5. Can you explain how to multiply and divide fractions with exponents?

**Tip**: When dealing with negative exponents, remember that it essentially involves taking the reciprocal of the base and changing the sign of the exponent to positive.

Find the value of (7/8)^(-2) by applying the reciprocal rule for negative exponents. This problem involves key concepts like negative exponents and fractions. A step-by-step solution is provided, suitable for students in Grades 8-10.

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