Math Problem Statement
Evaluate definite integral of sin(x) from π to 3π/2 using Bethe-Salpeter's method of numerical integration
Solution
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Math Problem Analysis
Mathematical Concepts
Definite Integral
Trigonometric Functions
Formulas
I = ∫sin(x) dx
Antiderivative of sin(x) = -cos(x)
I = [-cos(x)] from π to 3π/2
Theorems
Fundamental Theorem of Calculus
Suitable Grade Level
Undergraduate (First Year Calculus)
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