The given expression is a definite integral:

$\int_0^6 6 \, dx$

Solution:

Since the integrand is a constant $6$, we can integrate it with respect to $x$.

$\int 6 \, dx = 6x + C$

Now, we apply the limits from 0 to 6:

$\left[ 6x \right]_0^6 = 6(6) - 6(0)$

$6(6) = 36 \quad \text{and} \quad 6(0) = 0$

Thus, the value of the integral is:

$36 - 0 = 36$

Final Answer:

$\int_0^6 6 \, dx = 36$

Would you like any further explanation or have any other questions?

5 Related Questions:

1. What is the general formula for integrating a constant function?
2. How do definite integrals differ from indefinite integrals?
3. How do you apply the Fundamental Theorem of Calculus?
4. What happens if the lower limit of an integral is larger than the upper limit?
5. How do you compute integrals with non-constant functions, like polynomials?

Tip:

When integrating constants, the result is always the constant multiplied by the variable of integration (plus any limits if it's a definite integral).