Given the function \( f(x) = x^3 - 1 \), and the value \( a = 7 \), we can evaluate the function at \( a \) by substituting \( x = 7 \) into the function:

\[
f(7) = 7^3 - 1
\]

Now calculate:

\[
7^3 = 343
\]
\[
f(7) = 343 - 1 = 342
\]

Thus, \( f(7) = 342 \).

Would you like more details or have any questions about this?

Here are 5 related questions:
1. What is the derivative of \( f(x) = x^3 - 1 \)?
2. Can you find \( f'(7) \), the slope of the tangent line at \( x = 7 \)?
3. What is the integral of \( f(x) = x^3 - 1 \)?
4. Can you find the roots of the equation \( f(x) = 0 \)?
5. How does the graph of \( f(x) = x^3 - 1 \) behave near \( x = 0 \)?

**Tip**: Always remember to check the behavior of a function by analyzing its derivatives for slopes and critical points!

Learn how to evaluate the cubic function f(x) = x^3 - 1 at x = 7. This problem involves key algebraic concepts and polynomial equations, suitable for students in Grades 9-11. Detailed steps are provided to understand the evaluation process.

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