Math Problem Statement

use the unit circle to evaluate each function

Use the unit circle to evaluate csc(7π/4)

Solution

To evaluate csc(7π4)\csc\left(\frac{7\pi}{4}\right) using the unit circle, let's proceed step-by-step:

Step 1: Identify the corresponding angle on the unit circle

The angle 7π4\frac{7\pi}{4} is in radians. Since one full circle is 2π2\pi radians, this angle exceeds 2π2\pi. However, we can subtract 2π2\pi from 7π4\frac{7\pi}{4} to find an equivalent angle: 7π4=2ππ4\frac{7\pi}{4} = 2\pi - \frac{\pi}{4} This tells us that 7π4\frac{7\pi}{4} corresponds to π4-\frac{\pi}{4} on the unit circle, which is in the fourth quadrant.

Step 2: Find the sine of 7π4\frac{7\pi}{4}

In the unit circle, the reference angle for 7π4\frac{7\pi}{4} is π4\frac{\pi}{4}, which has a sine value of 22\frac{\sqrt{2}}{2}. Since 7π4\frac{7\pi}{4} is in the fourth quadrant, where sine is negative, we have: sin(7π4)=22\sin\left(\frac{7\pi}{4}\right) = -\frac{\sqrt{2}}{2}

Step 3: Calculate the cosecant

Cosecant is the reciprocal of sine, so: csc(7π4)=1sin(7π4)=122=22=2\csc\left(\frac{7\pi}{4}\right) = \frac{1}{\sin\left(\frac{7\pi}{4}\right)} = \frac{1}{-\frac{\sqrt{2}}{2}} = -\frac{2}{\sqrt{2}} = -\sqrt{2}

Thus, csc(7π4)=2\csc\left(\frac{7\pi}{4}\right) = -\sqrt{2}.

Would you like more details on any part of this solution?

Related Questions:

  1. What is the sine of 7π6\frac{7\pi}{6}?
  2. How do you calculate the cosine of 5π3\frac{5\pi}{3}?
  3. What is the tangent of 3π4\frac{3\pi}{4} using the unit circle?
  4. How do you evaluate sec(11π6)\sec\left(\frac{11\pi}{6}\right)?
  5. What is the value of cot(5π4)\cot\left(\frac{5\pi}{4}\right)?

Tip: When working with the unit circle, it's helpful to memorize the sine and cosine values of key angles such as π6,π4,\frac{\pi}{6}, \frac{\pi}{4}, and π3\frac{\pi}{3} for faster evaluations!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Unit Circle
Cosecant Function

Formulas

csc(θ) = 1/sin(θ)
Unit circle coordinates for angles

Theorems

Reference Angle Theorem

Suitable Grade Level

Grades 10-12