Math Problem Statement

Evaluate 6 + 4/a + b/3 when a = 4 and b = 3.

Solution

The problem is to evaluate the expression:

6+4a+b36 + \frac{4}{a} + \frac{b}{3}

where a=4a = 4 and b=3b = 3.

Step-by-Step Solution:

  1. Substitute the given values of aa and bb: 6+44+336 + \frac{4}{4} + \frac{3}{3}

  2. Simplify each fraction: 44=1,33=1\frac{4}{4} = 1, \quad \frac{3}{3} = 1

    So the expression becomes: 6+1+16 + 1 + 1

  3. Add the terms: 6+1+1=86 + 1 + 1 = 8

Final Answer:

8\boxed{8}

Would you like more details or additional examples?


Related Questions:

  1. How would the solution change if a=2a = 2 and b=6b = 6?
  2. Can you rewrite 6+4a+b36 + \frac{4}{a} + \frac{b}{3} in terms of only aa?
  3. What is the general rule for evaluating expressions with fractions and substitution?
  4. How does the order of operations affect similar problems?
  5. How can we simplify expressions with multiple fractions?

Tip:

Always simplify fractions first to make calculations easier when substituting values into expressions!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Substitution
Fractions

Formulas

Simplification of fractions: a/b
Order of operations (PEMDAS)

Theorems

-

Suitable Grade Level

Grades 6-8