To solve the given differential equation using Euler’s numerical method with step size h=0.1, we proceed as follows:
The given differential equation is:
dxdy+2xy=x,y(0)=2
Rewriting it in standard form for Euler's method:
dxdy=x−2xy
Define:
f(x,y)=x−2xy
Step-by-step process:
Initial conditions:
x0=0,y0=2
We calculate y iteratively at x=0.1,0.2,…,0.6.
Iteration formula:
yn+1=yn+h⋅f(xn,yn)
Here, h=0.1.
Iterations:
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At x0=0,y0=2:
f(0,2)=0−2(0)(2)=0
y1=y0+h⋅f(0,2)=2+0.1⋅0=2
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At x1=0.1,y1=2:
f(0.1,2)=0.1−2(0.1)(2)=0.1−0.4=−0.3
y2=y1+h⋅f(0.1,2)=2+0.1⋅(−0.3)=2−0.03=1.97
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At x2=0.2,y2=1.97:
f(0.2,1.97)=0.2−2(0.2)(1.97)=0.2−0.788=−0.588
y3=y2+h⋅f(0.2,1.97)=1.97+0.1⋅(−0.588)=1.97−0.0588=1.9112
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At x3=0.3,y3=1.9112:
f(0.3,1.9112)=0.3−2(0.3)(1.9112)=0.3−1.14672=−0.84672
y4=y3+h⋅f(0.3,1.9112)=1.9112+0.1⋅(−0.84672)=1.9112−0.084672=1.826528
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At x4=0.4,y4=1.826528:
f(0.4,1.826528)=0.4−2(0.4)(1.826528)=0.4−1.4612224=−1.0612224
y5=y4+h⋅f(0.4,1.826528)=1.826528+0.1⋅(−1.0612224)=1.826528−0.10612224=1.72040576
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At x5=0.5,y5=1.72040576:
f(0.5,1.72040576)=0.5−2(0.5)(1.72040576)=0.5−1.72040576=−1.22040576
y6=y5+h⋅f(0.5,1.72040576)=1.72040576+0.1⋅(−1.22040576)=1.72040576−0.122040576=1.598365184
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At x6=0.6,y6=1.598365184:
f(0.6,1.598365184)=0.6−2(0.6)(1.598365184)=0.6−1.9180382208=−1.3180382208
y7=y6+h⋅f(0.6,1.598365184)=1.598365184+0.1⋅(−1.3180382208)=1.598365184−0.13180382208=1.46656136192
Final Result:
y(0.6)≈1.467(rounded to three decimal places)
Would you like a detailed comparison with other methods or visual representation of the solution?
Related Questions:
- How can this solution be checked using an exact or analytical solution?
- What is the error associated with using Euler's method in this case?
- How does the step size h affect the accuracy of Euler's method?
- Can higher-order methods like the Runge-Kutta method improve the accuracy here?
- How does the behavior of the differential equation change for different initial conditions?
Tip: Euler's method is a simple numerical approach but can accumulate significant errors for large step sizes.