Math Problem Statement
The following table shows the wind chill C(T,w) (in °F ) as a function of the air temperature T (in °F ) and the wind speed w (in miles per hour)
according to the current National Weather Service model.
There are three ways to estimate a partial derivative from a table of values, the forward difference quotient (for example,
fx(a,b)~~f(a+h,b)-f(a,b)h with h>0 ), the backward difference quotient (for example, fx(a,b)~~f(a,b)-f(a-h,b)h with h>0 ), and the
symmetric difference quotient (for example, fx(a,b)~~f(a+h,b)-f(a-h,b)2h with h>0 ). The symmetric difference quotient is just the average
of the forward and backward difference quotients.
The forward difference quotient approximation to CT(30,15) is
°F°F. The backward difference quotient approximation to
CT(30,15) is
°F°F. The symmetric difference quotient approximation to CT(30,15) is
°F°F.
The forward difference quotient approximation to Cw(30,15) is
°Fmph. The backward difference quotient approximation to
Cw(30,15) is
°Fmph. The symmetric difference quotient approximation to Cw(30,15) is
°Fmph.
The National Weather Service has also provided an empirical formula for approximating the wind chill. It states that
C(T,w)~~35.74+0.6215T+w0.16(-35.75+0.4275T)
Based on this formula, CT(30,15)~~
°F°F and Cw(30,15)~~
°Fmph.
Solution
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Math Problem Analysis
Mathematical Concepts
Partial Derivatives
Difference Quotients
Empirical Formulas
Wind Chill
Formulas
Forward Difference Quotient: f_T(a, b) ≈ (f(a+h, b) - f(a, b)) / h
Backward Difference Quotient: f_T(a, b) ≈ (f(a, b) - f(a-h, b)) / h
Symmetric Difference Quotient: f_T(a, b) ≈ (f(a+h, b) - f(a-h, b)) / (2h)
Wind Chill Formula: C(T, w) ≈ 35.74 + 0.6215T + w^0.16(-35.75 + 0.4275T)
Theorems
Difference Quotients Approximation
Suitable Grade Level
College Level
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