Math Problem Statement

The following table shows the wind chill C(T,w) (in °F ) as a function of the air temperature T (in °F ) and the wind speed w (in miles per hour)

according to the current National Weather Service model.

There are three ways to estimate a partial derivative from a table of values, the forward difference quotient (for example,

fx(a,b)~~f(a+h,b)-f(a,b)h with h>0 ), the backward difference quotient (for example, fx(a,b)~~f(a,b)-f(a-h,b)h with h>0 ), and the

symmetric difference quotient (for example, fx(a,b)~~f(a+h,b)-f(a-h,b)2h with h>0 ). The symmetric difference quotient is just the average

of the forward and backward difference quotients.

The forward difference quotient approximation to CT(30,15) is

°F°F. The backward difference quotient approximation to

CT(30,15) is

°F°F. The symmetric difference quotient approximation to CT(30,15) is

°F°F.

The forward difference quotient approximation to Cw(30,15) is

°Fmph. The backward difference quotient approximation to

Cw(30,15) is

°Fmph. The symmetric difference quotient approximation to Cw(30,15) is

°Fmph.

The National Weather Service has also provided an empirical formula for approximating the wind chill. It states that

C(T,w)~~35.74+0.6215T+w0.16(-35.75+0.4275T)

Based on this formula, CT(30,15)~~

°F°F and Cw(30,15)~~

°Fmph.

Solution

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Partial Derivatives
Difference Quotients
Empirical Formulas
Wind Chill

Formulas

Forward Difference Quotient: f_T(a, b) ≈ (f(a+h, b) - f(a, b)) / h
Backward Difference Quotient: f_T(a, b) ≈ (f(a, b) - f(a-h, b)) / h
Symmetric Difference Quotient: f_T(a, b) ≈ (f(a+h, b) - f(a-h, b)) / (2h)
Wind Chill Formula: C(T, w) ≈ 35.74 + 0.6215T + w^0.16(-35.75 + 0.4275T)

Theorems

Difference Quotients Approximation

Suitable Grade Level

College Level