Math Problem Statement

I need help with c) and d)

I need help with c) and d)

Solution

Let's work through parts (c) and (d) of the problem step by step.

Part (c)

Problem Statement: The task is to estimate the population of the United States in 1970 using the logistic model. Then, you need to compare this estimate to the actual population of 203 million in 1970. The given logistic model is:

P(t)=11+1K(P0KP0)ertP(t) = \frac{1}{1 + \frac{1}{K} \cdot \left( \frac{P_0}{K - P_0} \right) \cdot e^{-rt}}

where:

  • P(t)P(t) is the population at year tt,
  • P0P_0 is the initial population (at t=0t = 0),
  • KK is the carrying capacity (maximum population the environment can sustain),
  • rr is the growth rate.

To apply this, you'll first need to estimate the parameters KK, rr, and P0P_0.

Steps to solve:

  1. Determine the values for KK, rr, and P0P_0.

    • From the table, choose a year to represent t=0t = 0. Typically, you might choose 1790 (first year in the table).
    • P0P_0 would then be the population in 1790, which is P0=3.929P_0 = 3.929 million.
    • KK needs to be estimated from the data. Since the U.S. population was rapidly increasing, you'll need to assume a plausible KK value or calculate one based on observed growth.
  2. Estimate KK and rr by fitting the logistic model to the given data. This typically requires more advanced statistical or computational tools.

  3. Predict P(t)P(t) for t=180t = 180 years after 1790 (i.e., in 1970).

  4. Compare the predicted value P(180)P(180) to the actual population in 1970.

Part (d)

Problem Statement: The task is to determine when the population in the U.S. was growing most rapidly and to explain how the logistic model determines this. The population grows most rapidly at the inflection point, where the second derivative of P(t)P(t) with respect to ( t \

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Math Problem Analysis

Mathematical Concepts

Logistic Growth Model
Population Modeling
Exponential Growth

Formulas

P(t) = 1 / [1 + (1/K) * (P0 / (K - P0)) * e^(-rt)]

Theorems

Logistic Growth Theorem

Suitable Grade Level

Grades 11-12