Math Problem Statement

What value should be used to estimate \(\sqrt{50}\) using the nearest function?

Solution

The image shows a table with squares of values and their corresponding square roots, and a question asking which value should be used to find 50\sqrt{50} using the nearest function.

The table is divided into two sections:

  1. First Section:

    • Squares: 5.025.0^2, 5.125.1^2, 5.225.2^2, 5.325.3^2, 5.425.4^2
    • Values: 25.0, 26.0, 27.0, 28.1, 29.2, 30.3
  2. Second Section:

    • Squares: 5.625.6^2, 5.725.7^2, 5.825.8^2, 5.925.9^2, 6.026.0^2
    • Values: 31.4, 32.5, 33.6, 34.8, 36.0

Analyzing the Table:

To estimate 50\sqrt{50}, look for the square that is closest to 50.

From the given squares:

  • 5.62=31.45.6^2 = 31.4
  • 5.72=32.55.7^2 = 32.5
  • 5.82=33.65.8^2 = 33.6
  • 5.92=34.85.9^2 = 34.8
  • 6.02=36.06.0^2 = 36.0

None of these values in the table reach close to 50 directly, but understanding that 50\sqrt{50} lies between the squares of 7.0 and 7.1 might lead to the correct choice.

50\sqrt{50} is approximately 7.071, which is close to 7.1. So, the square root calculation closest to 7.0717.071 could be in a square table of squares above 6.026.0^2.

Thus, the correct answer would likely use squares of 7.027.0^2 or 7.127.1^2 to calculate 50\sqrt{50}.

Would you like more details or have any questions? Here are 5 relative questions you might find useful:

  1. How do you calculate square roots using interpolation between given squares?
  2. What is the significance of choosing a nearby square for estimating square roots?
  3. Can you use this method for non-perfect squares, like 55\sqrt{55}?
  4. How does the nearest square method compare to using a calculator for square roots?
  5. What are other methods to approximate square roots without a calculator?

Tip: Understanding square values and their roots helps in quickly estimating square roots, especially in exams where calculators are not allowed.

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Math Problem Analysis

Mathematical Concepts

Square Roots
Estimation
Squares

Formulas

\(\sqrt{x}\approx y\) if \(y^2\) is close to \(x\)

Theorems

Approximation of square roots using nearest squares

Suitable Grade Level

Grades 6-8