Math Problem Statement

(a) Complete the table below given f(x)=x+13−x−−−−√−2 .

Round your answers to four decimal places.

x −1.1 −1.01 −1.001 −0.999 −0.99 −0.9

f(x)

Number Number Number Number Number Number

(b) Estimate limx→−1(x+13−x−−−−√−2)

Solution

Let's break this problem into two parts:

Part (a): Completing the Table

We are given the function f(x)=x+13x2f(x) = \frac{x + 13 - \sqrt{-x}}{2} and asked to compute the values of f(x)f(x) for specific xx-values. We will plug in the values of xx into the function and calculate them, rounding the results to four decimal places.

The values of xx to compute are: 1.1-1.1, 1.01-1.01, 1.001-1.001, 0.999-0.999, 0.99-0.99, and 0.9-0.9.

I'll compute each value and fill the table.

f(x)=x+13x2f(x) = \frac{x + 13 - \sqrt{-x}}{2}

Let me compute these values now.Here is the completed table with the calculated values of f(x)f(x):

\hline x & f(x) \\ \hline -1.1 & 5.4256 \\ -1.01 & 5.4925 \\ -1.001 & 5.4993 \\ -0.999 & 5.5008 \\ -0.99 & 5.5075 \\ -0.9 & 5.5757 \\ \hline \end{array}$$ ### Part (b): Estimating $$\lim_{x \to -1} \left( \frac{x + 13 - \sqrt{-x}}{2} \right)$$ From the table, as $$x$$ approaches $$-1$$, the values of $$f(x)$$ appear to be approaching approximately $$5.5$$. Therefore, we can estimate: $$\lim_{x \to -1} \left( \frac{x + 13 - \sqrt{-x}}{2} \right) \approx 5.5$$ Would you like more details or have any questions? Here are 5 related questions to consider: 1. What happens to the function as $$x \to 0$$? 2. Can the function be simplified for larger $$x$$-values? 3. How does the square root of negative $$x$$ affect the function’s behavior? 4. What would happen if $$x$$ approached positive values close to zero? 5. Can you find the derivative of $$f(x)$$? **Tip:** When estimating limits numerically, look at the trend of the function's output as the input values approach the limit.

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Math Problem Analysis

Mathematical Concepts

Limits
Algebra
Square Roots
Function Analysis

Formulas

f(x) = (x + 13 - sqrt(-x))/2

Theorems

Limit Theorem

Suitable Grade Level

Grades 11-12