Math Problem Statement

Consider the graph of y = f(x) shown below in blue. Estimate the value of the derivative at x = -1. Then select the answer that most closely matches your computed value for f'(-1).

Solution

The problem asks for the estimation of the derivative of the function f(x)f(x) at x=1x = -1 by examining the graph.

To estimate the derivative f(1)f'(-1), we need to calculate the slope of the tangent line to the curve at x=1x = -1.

From the graph:

  • At x=1x = -1, the function f(x)f(x) is around y=2y = 2.
  • We can estimate the slope of the tangent line by observing how f(x)f(x) changes around x=1x = -1. The function is increasing as xx moves from left to right at this point.

To estimate the slope:

  1. Between x=2x = -2 and x=0x = 0, the function rises from approximately y=1y = -1 at x=2x = -2 to y=4y = 4 at x=0x = 0.

    Slope between these points: slope=ΔyΔx=4(1)0(2)=52=2.5\text{slope} = \frac{\Delta y}{\Delta x} = \frac{4 - (-1)}{0 - (-2)} = \frac{5}{2} = 2.5

    Since the graph appears somewhat linear near x=1x = -1, the derivative f(1)f'(-1) is likely close to 2.5.

Thus, the estimated value of the derivative at x=1x = -1 is approximately 2.5.

Would you like to explore more details about estimating derivatives from graphs?

Here are 5 related questions to extend the learning:

  1. How do you determine the slope of a curve at a specific point?
  2. What is the significance of a derivative in relation to a graph?
  3. How can you visually distinguish between increasing and decreasing slopes on a graph?
  4. How would the derivative behave at a local maximum or minimum?
  5. What are the steps to compute the derivative algebraically if the function was provided?

Tip: The steeper the graph, the higher the derivative value. Conversely, if the graph flattens, the derivative approaches zero.

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Math Problem Analysis

Mathematical Concepts

Derivatives
Slope of Tangent Line
Rate of Change
Graph Interpretation

Formulas

f'(x) = (f(x+h) - f(x)) / h

Theorems

Tangent Line Approximation
Derivative as Slope of Tangent Line

Suitable Grade Level

Grades 11-12