To determine the error interval for $x$, given that $x$ is rounded to two decimal places as $7.19$:

1. The rounding to two decimal places means $x$ could be slightly less than $7.19$ or slightly greater than $7.19$, but still rounds to $7.19$.
2. The range of $x$ is defined by the halfway points between $7.19$ and its nearest two decimal neighbors ($7.18$ and $7.20$).

Calculation:

• The lower bound: $7.185$
• The upper bound: $7.195$ (not inclusive).

Error interval:

$7.185 \leq x < 7.195$

Let me know if you need further clarifications or help!

Here are 5 related questions for practice:

1. How do you calculate error intervals for a number rounded to the nearest whole number?
2. What would be the error interval for a number rounded to one decimal place as $5.4$?
3. Why is the upper bound in the interval not inclusive?
4. How does the size of the rounding place affect the width of the error interval?
5. Can an error interval contain numbers that do not round to the specified rounded value?

Tip: When working with rounding and error intervals, always identify the precision (decimal places) and boundaries clearly.