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The question asks for the error interval for a number \( y \), which is rounded to 14.3 to 1 decimal place.

When a number is rounded to 1 decimal place (1 d.p.), the error interval is determined by finding the range within which the actual value of the number lies. The error interval for rounding to 1 decimal place is \(\pm 0.05\), as this is half the value of the place being rounded.

### Solution:
- The lower bound of the error interval is \(14.3 - 0.05 = 14.25\).
- The upper bound of the error interval is \(14.3 + 0.05 = 14.35\).

Thus, the error interval for \( y \) is:
\[
14.25 \leq y < 14.35
\]

This means \( y \) could be any value from 14.25 up to, but not including, 14.35.

Would you like more details or further explanation?

Here are 5 related questions to expand your understanding:
1. What is the error interval for a number rounded to 2 decimal places?
2. How do you calculate the error interval for a number rounded to the nearest whole number?
3. What is the significance of using a strict inequality for the upper bound of an error interval?
4. How would the error interval change if \( y \) were rounded to 2 significant figures instead of 1 decimal place?
5. Can you determine the error interval for a number rounded to the nearest tenth?

**Tip:** When working with error intervals, always remember that the upper bound is exclusive when writing the interval using inequalities!

A number, y, rounded to 1 decimal place is 14.3. Write down the error interval for y.

Learn how to calculate the error interval for a number rounded to 1 decimal place. The error interval for a number like 14.3, rounded to 1 decimal place, is 14.25 ≤ y < 14.35. Suitable for students in Grades 7-9.

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