Math Problem Statement

A number, y, rounded to 1 decimal place is 14.3. Write down the error interval for y.

Solution

The question asks for the error interval for a number yy, which is rounded to 14.3 to 1 decimal place.

When a number is rounded to 1 decimal place (1 d.p.), the error interval is determined by finding the range within which the actual value of the number lies. The error interval for rounding to 1 decimal place is ±0.05\pm 0.05, as this is half the value of the place being rounded.

Solution:

  • The lower bound of the error interval is 14.30.05=14.2514.3 - 0.05 = 14.25.
  • The upper bound of the error interval is 14.3+0.05=14.3514.3 + 0.05 = 14.35.

Thus, the error interval for yy is: 14.25y<14.3514.25 \leq y < 14.35

This means yy could be any value from 14.25 up to, but not including, 14.35.

Would you like more details or further explanation?

Here are 5 related questions to expand your understanding:

  1. What is the error interval for a number rounded to 2 decimal places?
  2. How do you calculate the error interval for a number rounded to the nearest whole number?
  3. What is the significance of using a strict inequality for the upper bound of an error interval?
  4. How would the error interval change if yy were rounded to 2 significant figures instead of 1 decimal place?
  5. Can you determine the error interval for a number rounded to the nearest tenth?

Tip: When working with error intervals, always remember that the upper bound is exclusive when writing the interval using inequalities!

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Math Problem Analysis

Mathematical Concepts

Rounding
Error Intervals
Inequalities

Formulas

Error Interval: Lower bound = Rounded value - 0.05, Upper bound = Rounded value + 0.05

Theorems

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Suitable Grade Level

Grades 7-9