Math Problem Statement

The "≡ mod 3" relation is an equivalence relation on the set {1, 2, 3, 4, 5, 6, 7}. List the equivalence classes.

Solution

To determine the equivalence classes under the relation "≡ mod 3" for the set {1,2,3,4,5,6,7}\{1, 2, 3, 4, 5, 6, 7\}, we group elements that are congruent to each other modulo 3. Two numbers aa and bb are in the same equivalence class if and only if ab(mod3)a \equiv b \pmod{3}, meaning the remainder when aa and bb are divided by 3 is the same.

Steps:

  1. Compute the remainder when each element of the set is divided by 3.
  2. Group elements with the same remainder.

Calculation:

  • 1÷3=0 remainder 1    11(mod3)1 \div 3 = 0 \text{ remainder } 1 \implies 1 \equiv 1 \pmod{3}
  • 2÷3=0 remainder 2    22(mod3)2 \div 3 = 0 \text{ remainder } 2 \implies 2 \equiv 2 \pmod{3}
  • 3÷3=1 remainder 0    30(mod3)3 \div 3 = 1 \text{ remainder } 0 \implies 3 \equiv 0 \pmod{3}
  • 4÷3=1 remainder 1    41(mod3)4 \div 3 = 1 \text{ remainder } 1 \implies 4 \equiv 1 \pmod{3}
  • 5÷3=1 remainder 2    52(mod3)5 \div 3 = 1 \text{ remainder } 2 \implies 5 \equiv 2 \pmod{3}
  • 6÷3=2 remainder 0    60(mod3)6 \div 3 = 2 \text{ remainder } 0 \implies 6 \equiv 0 \pmod{3}
  • 7÷3=2 remainder 1    71(mod3)7 \div 3 = 2 \text{ remainder } 1 \implies 7 \equiv 1 \pmod{3}

Grouping by Remainders:

  • Numbers with remainder 00: {3,6}\{3, 6\}
  • Numbers with remainder 11: {1,4,7}\{1, 4, 7\}
  • Numbers with remainder 22: {2,5}\{2, 5\}

Equivalence Classes:

The equivalence classes under the relation (mod3)≡ \pmod{3} are:

  1. [0]={3,6}[0] = \{3, 6\}
  2. [1]={1,4,7}[1] = \{1, 4, 7\}
  3. [2]={2,5}[2] = \{2, 5\}

Let me know if you'd like further clarification or have questions!


Related Questions:

  1. How can equivalence relations be visualized using modular arithmetic?
  2. What are the properties of equivalence relations and how do they apply here?
  3. Can we generalize this equivalence class concept for other moduli, like mod 4 or mod 5?
  4. How would the equivalence classes change if the set were expanded, e.g., {1,2,,10}\{1, 2, \dots, 10\}?
  5. How can equivalence classes be used in solving systems of congruences?

Tip: Remember that equivalence classes partition the set into disjoint subsets where every element belongs to exactly one class.

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Math Problem Analysis

Mathematical Concepts

Equivalence Relations
Modular Arithmetic

Formulas

a ≡ b (mod n)

Theorems

Equivalence Relations Partition a Set

Suitable Grade Level

Grades 9-12