We are asked to calculate the tension in each string that supports a body in equilibrium. The key details are:

• The body weighs $700 \, \text{N}$, which acts as the force due to gravity at point $P$.
• We know the lengths of the strings:
  • $|PM| = 1.5 \, \text{m}$
  • $|PT| = 2.0 \, \text{m}$
  • $|MT| = 2.8 \, \text{m}$

Since the body is in equilibrium, the sum of the forces acting on the body must be zero. This includes both the vertical and horizontal components of the forces from the tension in the strings.

Step 1: Consider a Triangle with Known Sides

We can treat the system as a triangle with the sides $PM$, $PT$, and $MT$. Using these, we can calculate the angles at each point using the cosine rule.

The cosine rule is: $\cos(\theta) = \frac{a^2 + b^2 - c^2}{2ab}$ where $a$, $b$, and $c$ are the sides of the triangle, and $\theta$ is the angle opposite side $c$.

Angle at $P$ (between strings $PM$ and $PT$):

Applying the cosine rule, we have: $\cos(\theta_P) = \frac{PM^2 + PT^2 - MT^2}{2 \times PM \times PT}$ $\cos(\theta_P) = \frac{(1.5)^2 + (2.0)^2 - (2.8)^2}{2 \times 1.5 \times 2.0}$

Let me calculate this angle for you.The angle at point $P$ (between the strings $PM$ and $PT$) is approximately $105.37^\circ$.

Step 2: Resolve Tensions

Since the body is in equilibrium, we can now apply Lami’s theorem or resolve the tensions into their horizontal and vertical components. Would you like to proceed with Lami's theorem or use the method of resolving forces?