Math Problem Statement

De lijn l gaat door het punt B(9, 3) en is evenwijdig met de lijn m: y = -1/2x + 4. Stel de formule op van l.

Solution

The image shows a mathematical problem in Dutch. Here is the translation and interpretation of the text:


b. The line ll passes through the point B(9,3)B(9, 3) and is parallel to the line m:y=12x+4m: y = -\frac{1}{2}x + 4.

Question: Write the equation of line ll.


Solution:

Since line ll is parallel to line mm, they have the same slope. The equation of line mm is given as:

y=12x+4y = -\frac{1}{2}x + 4

Thus, the slope of line mm is 12-\frac{1}{2}. Since parallel lines have equal slopes, the slope of line ll is also 12-\frac{1}{2}.

Now, using the point-slope form of the line equation, which is:

yy1=m(xx1)y - y_1 = m(x - x_1)

where (x1,y1)(x_1, y_1) is a point on the line and mm is the slope. For line ll, we have:

  • (x1,y1)=(9,3)(x_1, y_1) = (9, 3)
  • m=12m = -\frac{1}{2}

Substitute these values into the point-slope form:

y3=12(x9)y - 3 = -\frac{1}{2}(x - 9)

Simplifying:

y3=12x+92y - 3 = -\frac{1}{2}x + \frac{9}{2}

Add 3 to both sides to isolate yy:

y=12x+92+3y = -\frac{1}{2}x + \frac{9}{2} + 3

Convert 3 into a fraction:

y=12x+92+62y = -\frac{1}{2}x + \frac{9}{2} + \frac{6}{2}

Now, simplify:

y=12x+152y = -\frac{1}{2}x + \frac{15}{2}

Thus, the equation of the line ll is:

y=12x+152y = -\frac{1}{2}x + \frac{15}{2}

Do you want more details or have any questions?

Here are some related questions:

  1. How do you find the equation of a line given a point and the slope?
  2. What is the significance of parallel lines having the same slope?
  3. How can you convert a fraction into a decimal in a linear equation?
  4. How does changing the point affect the equation of the line?
  5. What if the lines were perpendicular instead of parallel? How would you find the equation?

Tip: Always remember that parallel lines share the same slope but differ in their y-intercepts!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Parallel Lines

Formulas

Point-slope form: y - y1 = m(x - x1)
Equation of a line: y = mx + c

Theorems

Slope of parallel lines is the same

Suitable Grade Level

Grades 9-12