The graph shows a line passing through the points $(-4, 3)$ and $(4, -3)$.

Steps to find the equation of the line:

1. Find the slope (m): The slope $m$ of a line passing through two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: $m = \frac{y_2 - y_1}{x_2 - x_1}$ Substituting the points $(-4, 3)$ and $(4, -3)$: $m = \frac{-3 - 3}{4 - (-4)} = \frac{-6}{8} = -\frac{3}{4}$ So, the slope $m = -\frac{3}{4}$.

2. Use the point-slope form of the equation: The equation of a line with slope $m$ through a point $(x_1, y_1)$ is given by: $y - y_1 = m(x - x_1)$ Using the point $(-4, 3)$ and the slope $m = -\frac{3}{4}$: $y - 3 = -\frac{3}{4}(x + 4)$

3. Simplify the equation: $y - 3 = -\frac{3}{4}x - 3$ Adding 3 to both sides: $y = -\frac{3}{4}x$

So, the equation of the line is: $y = -\frac{3}{4}x$

Would you like a detailed breakdown of any step, or have any other questions?

Here are some related questions:

1. How would the equation change if the slope were positive?
2. What if the line passed through the origin—how would the equation look?
3. Can you convert this equation into standard form $Ax + By = C$?
4. What is the y-intercept of this line?
5. How would you graph this equation by hand?

Tip: To find the slope easily from a graph, you can count the "rise over run" between two clear points.